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3 years ago

What assumption should be made to prove this conjecture by contradiction? If it is raining, then I will not go swimming.

1 answer:

8 0

Here are some options to make deciding easier-

A) you went swimming
B) it is raining
C)you are not swimming
D) it is not raining

I think that the answer would be A because the opposite of it not raining would be it raining and the effect of that is that you will go swimming.

Hope this helps... plz mark Brainliest :)

You might be interested in

Grady marks down some $4.09 pens to $3.59 for a week and then marks them back up to $4.09. Find the percent of increase and the

emmainna [20.7K]

Answer:

Percentage decrease ( from $4.09 to $3.59) is 0.1% ( Rounded to nearest tenth)

Percentage increase (from $3.59 to 4.09) is 0.1% ( Rounded to nearest tenth)

Percentages are not same for the both price changes. As we can see from the calculations percentage change from $3.59 to $4.09 is higher.

Step-by-step explanation:

$4.09 has been changed to $3.59.

Percent change = [(Value after - Value before) / Value before]*100

= $\frac{3.59-4.09}{4.09}*100$ %

= $\frac{-0.5}{4.09}*100$ %

= $-0.122249$ %

= $-0.1$ % ( Rounded to nearest tenth)

Percentage decrease is 0.1% ( Rounded to nearest tenth)

Now lets calculate the percentage change from $3.59 to $4.09.

Percent change = [(Value after - Value before) / Value before]*100

= $\frac{4.09-3.59}{3.59}*100$ %

= $\frac{0.5}{3.59}*100$ %

= $0.13927$ %

= $0.1$ % ( Rounded to nearest tenth)

Percentage increase is 0.1% ( Rounded to nearest tenth)

Percentages are not same for the both price changes. As we can see from the calculations percentage change from $3.59 to $4.09 is higher.

6 0

3 years ago

(U...

Tresset [83]

Answer:

the 19th term of the arithmetic sequence is 73.

Step-by-step explanation:

Given:

The arithmetic sequence whose common difference is

$d=4$

And first term is

$a=1$

Find the 19th term of the arithmetic sequence

$n=19$

Now we know that,

$a_{n}=a+(n-1)d$

Put all the value in above AP.

$a_{19}= 1+(19-1)4$

$a_{19}= 1+18\times 4$

$a_{19}= 1+72$

$a_{19}= 73$

So, $19_{th}$ term of the sequence is 73.

3 0

3 years ago

If there are 60 miles in each walk how many walks can you walk in 3 miles

Radda [10]

Answer:

0.15 of a walk

Step-by-step explanation:

2/60 =0.15

Therefore you can walk 0.15 of a walk(so confused lol)

5 0

2 years ago

An amount of $700 was invested at 7% for 7 months. What is the interest? Round your

Levart [38]

Answer:

49 dollars

Step-by-step explanation:

700 times .07

7 0

2 years ago

Molly was on a long 136 mile road trip. The first part of the trip there was lots of traffic, she only averaged 16 mph. The seco

Mazyrski [523]

Answer:

In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

Explanation:

Given that the road trip was 136 miles;

$d=136$

The first part of the trip there was lots of traffic, she only averaged 16 mph;

$v_1=16$

The second part of the trip there was no traffic so she could drive 44 mph;

$v_2=44$

She traveled for a total of 5 hours;

$t=5$

let x represent the time in traffic when she traveled at 16 mph

$t_1=x$

the time the traffic is clear would be;

$t_2=t-t_1=5-x$

Recall that distance equals speed multiply by time;

$d=v_1t_1_{}_{}^{}+v_2t_2$

substituting the values;

$136=16x+44(5-x)$

solving for x;

$\begin{gathered} 136=16x+220-44x \\ 44x-16x=220-136 \\ 28x=84 \\ x=\frac{84}{28} \\ x=3 \end{gathered}$

So;

$\begin{gathered} t_1=3\text{ hours} \\ t_2=5-x=5-3=2 \\ t_2=2\text{ hours} \end{gathered}$

Therefore, In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

7 0

1 year ago