Answer:
Part A
The bearing of the point 'R' from 'S' is 225°
Part B
The bearing from R to Q is approximately 293.2°
Step-by-step explanation:
The location of the point 'Q' = 35 km due East of P
The location of the point 'S' = 15 km due West of P
The location of the 'R' = 15 km due south of 'P'
Part A
To work out the distance from 'R' to 'S', we note that the points 'R', 'S', and 'P' form a right triangle, therefore, given that the legs RP and SP are at right angles (point 'S' is due west and point 'R' is due south), we have that the side RS is the hypotenuse side and ∠RPS = 90° and given that
=
, the right triangle ΔRPS is an isosceles right triangle
∴ ∠PRS = ∠PSR = 45°
The bearing of the point 'R' from 'S' measured from the north of 'R' = 180° + 45° = 225°
Part B
∠PRQ = arctan(35/15) ≈ 66.8°
Therefore the bearing from R to Q = 270 + 90 - 66.8 ≈ 293.2°
The third graph represents the data because the values in the table are identical to the ones plotted on that graph.
Answer:
-15?
Step-by-step explanation:
It's hard to tell where the point is exactly
Answer:
It is a value that is an abnormal distance from the other values in a data set.
Step-by-step explanation:
An outlier is something that stands out from another thing. Such as color in a black and white film.
Answer:
m<JKD = 22 degrees
Step-by-step explanation:
21x + 5 + 4x + 2 = 132
25x + 7 = 132
25x = 125
x = 5
m<JKD = 4x + 2
4(5) + 2
20 + 2
22