What are the roots of the polynomial equation x^4+x^3=4x^2+4x? Use a graphing calculator and a system of equations.
2 answers:
Desmos graphing calculator will draw this graph for you. draw 2 curves y = x^4 + x^3 and y = 4x^2 + 4x The roots are the points where the 2 curves intersect. You can see by simple substitution that one root is zero. x^4 + x^3 - 4x^2 - 4x = 0 f(2) = 16 + 8 - 4(4) - 4(2) = 0 so 2 is another root f(-2) = 16 - 8 - 16 + 8 = 0 so -2 is another root f(-1) = 1 - 1 - 4 + 4 = 0 so -1 is the other root The answer is A
the answer is a i hope that helpful
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Answer:
Step-by-step explanation:
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Answer:
y = -4
Step-by-step explanation:
12y + 4 = 8y-12
Subtract 8y from each side
12y - 8y +4 = -12
4y +4 = -12
Subtract 4 from each side
4y +4-4 = -12 -4
4y = -16
Divide by 4
4y/4 = -16/4
y = -4