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What are the roots of the polynomial equation x^4+x^3=4x^2+4x? Use a graphing calculator and a system of equations.
2 answers:
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Answer: 6
Step-by-step explanation:
Let's use a rule of three here.
2 rooms in 1/3 h
x rooms in 1 h
Solve for x;
Remember that when you divide by a fraction, you invert the fraction and multiply by the numerator.
1/3 inverted is 3/1 or 3
$=(a^2-10a)-(b^2+6b) +16$
$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$
$=(a-5)^2-25-(b+3)^2+9+16$
$=(a-5)^2-(b+3)^2$
