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Marta_Voda [28]
3 years ago
5

MATH!!! I HAVE NO IDEA HOW TO DO THIS PLEASE SHOW ME THE WORK I WANNA KNOW HOW TO DO THIS FOR THE NEXT QUESTION!!!!​

Mathematics
1 answer:
zimovet [89]3 years ago
6 0

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

Answer:

Sorry I'm late!

Step-by-step explanation:

<em>Formula ⇒ </em>A = \frac{1}{2}bh

A = \frac{1}{2}bh

A = \frac{1}{2}(5)(7)

A = \frac{1}{2}(35)

A = 17.5

<h3>The Area of the face of the triangle is 17.5 in²</h3>

I hope this helps!

- sincerelynini

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Given:

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The total surface area is,

\begin{gathered} S=2\pi rh+2\pi(r)^2 \\ 96=2\pi xh+2\pi(x^2) \\ h=\frac{96-2\pi(x^2)}{2\pi x} \end{gathered}

Volume is,

\begin{gathered} V=\pi(r)^2h \\ =\pi(x^2)\frac{96-2\pi(x^2)}{2\pi x} \\ =\frac{x(96-2\pi(x^2)}{2} \end{gathered}

Now, differentiate with respect to x,

\begin{gathered} \frac{dV}{dx}^{}=\frac{d}{dx}(\frac{x(96-2\pi(x^2)}{2}) \\ =\frac{d}{dx}\mleft(x\mleft(-\pi x^2+48\mright)\mright) \\ =\frac{d}{dx}\mleft(x\mright)\mleft(-\pi x^2+48\mright)+\frac{d}{dx}\mleft(-\pi x^2+48\mright)x \\ =1\cdot\mleft(-\pi x^2+48\mright)+\mleft(-2\pi x\mright)x \\ =84-3\pi(x^2)\ldots\ldots\ldots\ldots\text{.}(1) \end{gathered}

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\begin{gathered} \frac{dV}{dx}=0 \\ 84-3\pi(x^2)=0 \\ x^2=\frac{16}{\pi} \\ x=\sqrt[]{\frac{16}{\pi}} \end{gathered}

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\begin{gathered} \frac{d^2V}{dx^2}=\frac{d}{dx}(84-3\pi(x^2)) \\ =-6\pi x \\ At\text{ x=}\sqrt[]{\frac{16}{\pi}} \\ \frac{d^2V}{dx^2}=-6\pi\sqrt[]{\frac{16}{\pi}}

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