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emmainna [20.7K]
3 years ago
9

Round 9 991 to the nearest thousands

Mathematics
2 answers:
zaharov [31]3 years ago
6 0

9,990 first digit is like 1, then 10, then 100, then 1000 so the fourth digit being 1 goes to 0 when rounding

Luden [163]3 years ago
3 0

When rounding to the nearest thousand, you look at the following number to know if you go up or stay. In the case of 9,991:

9,<u>9</u>91     <em>If the 2nd largest digit is ≥ 5, then round up.</em>

10,000

Therefore, you would round 9.991 to 10,000.

<em>Hope this helps! :)</em>

<u><em>Edit: I literally solved for the wrong thing earlier lol; fixed it.</em></u>

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In ΔLMN, the measure of ∠N=90°, the measure of ∠M=66°, and MN = 8.7 feet. Find the length of LM to the nearest tenth of a foot.
vivado [14]

Answer: 21.4

Step-by-step explanation:

If you are here from delta math this is the answer

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3 years ago
in all, how many counting numbers from 200 to 500 are divisible by all of the following 2, 3, 4,5 and 6?
Arte-miy333 [17]

Answer:

I think its  6 numbers  . See below

Step-by-step explanation:

The numbers must end in 0 because they must be divisible by 2 and 5

240 is one number it is the first number between 200 and 500 which is divisible by the 5 numbers.

The LCM of the 5 numbers is  60 so we can add  300, 360, 420 and 480 to the list.

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3 years ago
How do you solve fore x/3 - x/5 = 2
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4 0
3 years ago
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Solve this equation -4(X-26)=-200
jek_recluse [69]

Answer:

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5 0
2 years ago
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Which of the following is true of the location of an angle, Theta, whose tangent value is Negative StartFraction StartRoot 3 End
Anuta_ua [19.1K]

The value of theta has a 30-degree reference angle and is located in Quadrant II or IV.

Given to us

tan \theta =-\dfrac{\sqrt{3}}{3}

<h3>What is the value of tan \theta =\dfrac{\sqrt{3}}{3}?</h3>

To know the value  tan \theta =\dfrac{\sqrt{3}}{3} we will simplify the given expression,

tan \theta =\dfrac{\sqrt{3}}{3}\\\\\\tan \theta =\dfrac{1}{\sqrt{3}}\\\\tan \theta =30^o

Hence, the value of theta is 30°.

<h3>Finding the location of the - tan30°?</h3>

To know that the location of the -tan30°,

tan30^o = -\dfrac{sin30^o}{cos30^o}

As the value is negative, therefore, there can be two cases,

Case I: when the value of Sin30° is negative,

Case II: when the value of cos30° is negative.

Case I: when the value of Sin30° is negative,

If the value of Sin30° is negative, while the value of cos30° is positive, the θ will lie in the fourth quadrant.

Case II: when the value of Cos30° is negative,

If the value of Cos30° is negative, while the value of Sin30° is positive, the θ will lie in the second quadrant.

Hence, the value of theta has a 30-degree reference angle and is located in Quadrant II or IV.

Learn more about Quadrants:

brainly.com/question/350459

5 0
3 years ago
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