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2 years ago

Solve for m in V = 3x + 2m - y.

Mathematics

1 answer:

jok3333 [9.3K]2 years ago

8 0

Answer:

$\large\boxed{m=\dfrac{V+y-3x}{2}}$

Step-by-step explanation:

$3x+2m-y=V\qquad\text{add}\ y\ \text{to both sides}\\\\3x+2m-y+y=V+y\\\\3x+2m=V+y\qquad\text{subtract}\ 3x\ \text{From both sides}\\\\3x-3x+2m=V+y-3x\\\\2m=V+y-3x\qquad\text{divide both sides by 2}\\\\\dfrac{2m}{2}=\dfrac{V+y-3x}{2}\\\\m=\dfrac{V+y-3x}{2}$

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Vlad1618 [11]

Answer:

C. D:{0, 1, 2, -4}- R:{1, -3, -4}

Step-by-step explanation:

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3 years ago

What is 5/11 minus negative 4/11

MA_775_DIABLO [31]

Answer: 1/11 and 0.09=0.10

Step-by-step explanation:

subtract by the numbers. subtract it's to take away one number from to another from the difference between the numbers.

5-4/11

5-4=1

=1/11

You can also round up to the nearest hundredths is 0.10.

Hope this helps!

Thanks!

Have a great day!

5 0

2 years ago

Read 2 more answers

Tamara and Clyde got different answers when dividing 2x4 + 7x3 – 18x2 + 11x – 2 by 2x2 – 3x + 1. Analyze their individual work.

lys-0071 [83]

Note: As you may have unintentionally missed to add the different answers, based on which we had to check who solved correctly between Tamara and Clyda's work.

But, I am actually solving the expression and you must note that whoever (between Tamara and Clyda's work) may have got the same answer or match the answer with mine, would be the one who solved correctly.

Answer:

We conclude that whoever (between Tamara and Clyda's work) may have got the answer as $x^2+5x-2$ after dividing $2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$ by $2x^2\:-\:3x\:+\:1$ , would be the one who solved it correctly.

Step-by-step explanation:

Considering the expression

$2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$

Lets divide the expression by $2x^2\:-\:3x\:+\:1$

Solution Steps:

$\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}$

Factorizing

$2x^4+7x^3-18x^2+11x-2:\quad \left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)$

$\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{2x^2-3x+1}$

Factorizing

$2x^2-3x+1:\quad \left(2x-1\right)\left(x-1\right)$

$\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}$

$\mathrm{Cancel\:}\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}:\quad x^2+5x-2$

$x^2+5x-2$

Thus,

$\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}=x^2+5x-2$

Therefore, we conclude that whoever (between Tamara and Clyda's work) may have got the answer as $x^2+5x-2$ after dividing $2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$ by $2x^2\:-\:3x\:+\:1$ , would be the one who solved it correctly.

Keywords: expression, division

Learn more about expression division from brainly.com/question/1575482

#learnwithBrainly

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2 years ago

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mojhsa [17]

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Hope that helps!!!

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2 years ago

Find the unit rate $28 for 7 people

Vlad1618 [11]

Answer: 4 dollars per person . that would be it .

Step-by-step explanation:

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2 years ago

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