Ask question

Ask question

All categories

3 years ago

8

Solve for m in V = 3x + 2m - y.

1 answer:

jok3333 [9.3K]3 years ago

8 0

Answer:

$\large\boxed{m=\dfrac{V+y-3x}{2}}$

Step-by-step explanation:

$3x+2m-y=V\qquad\text{add}\ y\ \text{to both sides}\\\\3x+2m-y+y=V+y\\\\3x+2m=V+y\qquad\text{subtract}\ 3x\ \text{From both sides}\\\\3x-3x+2m=V+y-3x\\\\2m=V+y-3x\qquad\text{divide both sides by 2}\\\\\dfrac{2m}{2}=\dfrac{V+y-3x}{2}\\\\m=\dfrac{V+y-3x}{2}$

You might be interested in

Rina8888 [55]

The answer is 1 mile an hour

5 0

3 years ago

Juli2301 [7.4K]

The answer is 3 : 1 since it’s raisin to pretzels. 6:2 in the simplest form there is, is 3:1.

6 0

3 years ago

Read 2 more answers

A bakery uses 3/10 of a cup of flour in one batch of biscuits. the bakery used 3/5 of a cup of flour yesterday. how many batches

nlexa [21]

The bakery made 3 batches of bicuits.
3/10=0.3
3/5=0.6
if 0.3 is 1 batch then 0.6 is 2 batches 1+2=3

7 0

3 years ago

Plzzzzz I need this answer

valentina_108 [34]

Answer:

the answer is the first one which is 3/32inch^3

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A club began with 3 members. Each month, each member brought one new member. Which function can be used to determine the number

skad [1K]

<h3>The needed function which represents the club members after x months is : $C(x) = 3+ (3)^x$ </h3>

Step-by-step explanation:

The initial members in the club = 3

⇒ a = 3

Also, let us assume the needed function is denoted by C(x).

Now, each member brings one new member in the club in 1 month.

So, the number of members in club after 1 month

= Initial members + Addition of members

= 3 + 3 = 6

or , $C(1) = 3 + (3)^1$

Now, at the starting of second month, initial members = 6

Each member brings 1 new member.

So, the number of new members at the end of second month = 6

Total members at the end of second month = 6+ 6 = 12

$\implies C(2) = 12 = 3 + (3)^2$

Continuing the same way, we can see that:

The number of members in club after x months is:

$C(x) = 3+ (3)^x$

Hence, the needed function is : $C(x) = 3+ (3)^x$

8 0

3 years ago