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Burka [1]
3 years ago
15

-6.8-c divided 1.2=-2.9

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
5 0

Answer:

3.44

Step-by-step explanation:

(-6.8 - c)  /  1.2  =  -2.8

(multiply both sides by 1.2)

-6.8 - c = -3.36

(add 6.8 to both sides)

-c = 3.44

c = 3.44

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Step-by-step explanation:

The other situations do not represent a 60% probability.

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3 years ago
Divide the 4th degree polynomial
iragen [17]

Answer:

  • quotient: 10x +16
  • remainder: 28x^2 +10x +22

Step-by-step explanation:

The attachment shows the steps.

  quotient: 10x +16

  remainder: 28x^2 +10x +22

_____

Polynomial long division is easier than numerical long division because you only need to examine the first terms to determine the quotient term.

The first quotient term is 10x^4/x^3 = 10x.

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When the leading dividend term is lower degree than the divisor, that dividend is the remainder.

4 0
3 years ago
Addison pays $36 for a 12-month magazine subscription. How much does Addison pay per month?
garik1379 [7]
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4 0
4 years ago
Read 2 more answers
All are properties of equality except:
erastova [34]
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7 0
3 years ago
Identify the standard form of the equation by completing the square.
OLEGan [10]

Answer:

\dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1

Step-by-step explanation:

<u>Given equation</u>:

4x^2-9y^2-8x+36y-68=0

This is an equation for a horizontal hyperbola.

<u>To complete the square for a hyperbola</u>

Arrange the equation so all the terms with variables are on the left side and the constant is on the right side.

\implies 4x^2-8x-9y^2+36y=68

Factor out the coefficient of the x² term and the y² term.

\implies 4(x^2-2x)-9(y^2-4y)=68

Add the square of half the coefficient of x and y inside the parentheses of the left side, and add the distributed values to the right side:

\implies 4\left(x^2-2x+\left(\dfrac{-2}{2}\right)^2\right)-9\left(y^2-4y+\left(\dfrac{-4}{2}\right)^2\right)=68+4\left(\dfrac{-2}{2}\right)^2-9\left(\dfrac{-4}{2}\right)^2

\implies 4\left(x^2-2x+1\right)-9\left(y^2-4y+4\right)=36

Factor the two perfect trinomials on the left side:

\implies 4(x-1)^2-9(y-2)^2=36

Divide both sides by the number of the right side so the right side equals 1:

\implies \dfrac{4(x-1)^2}{36}-\dfrac{9(y-2)^2}{36}=\dfrac{36}{36}

Simplify:

\implies \dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1

Therefore, this is the standard equation for a horizontal hyperbola with:

  • center = (1, 2)
  • vertices = (-2, 2) and (4, 2)
  • co-vertices = (1, 0) and (1, 4)
  • \textsf{Asymptotes}: \quad y = -\dfrac{2}{3}x+\dfrac{8}{3} \textsf{ and }y=\dfrac{2}{3}x+\dfrac{4}{3}
  • \textsf{Foci}: \quad  (1-\sqrt{13}, 2) \textsf{ and }(1+\sqrt{13}, 2)

4 0
2 years ago
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