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Aleonysh [2.5K]
3 years ago
15

Six plus four fifths A equals nine tenths A

Mathematics
1 answer:
Drupady [299]3 years ago
8 0
6+4/5a=9/10a
make bottom numbers same
into 10
60/10+8/10a=9/10a
minus 8/10a from both sides
60/10=1/10a
multiply both sides by 10
60=a
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Help I don't know what to put ​
olga55 [171]

Answer:

7

Step-by-step explanation:

plug in 3 where ever there is x

so

(4(3)+2)-7

use PEMDAS to solve from left to right

P: Parenthesis

E: Exponents

M: Multiplication

D: Division

A: Addition

S: Subtraction

so we got p so we do that first

(4(3)+2) --> 4 × 3 = 12 (Multiplication first like in PEMDAS)

(12+2) = 14

so then in the equation you are left with

(14)-7 = 7

answer is 7

6 0
3 years ago
Find a function rule for the line that passes through the origin (0,0) and the point (1, -16)
hodyreva [135]

Answer:

The answer is b and here’s the proof

Step-by-step explanation:

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B-16%7D%20-%5Csqrt%7B-3%7D%20%5Csqrt%7B-3%7D%20-%5Csqrt%7B-4%7D%20%5Csqrt%7B-4%7D%20%
sergeinik [125]

Answer:

<h2>4(i-1)</h2>

Step-by-step explanation:

Given the expression   \sqrt{-16} - \sqrt{-3} \sqrt{-3} -\sqrt{-4} \sqrt{-4}+3i-3i^{2} +3i^{3}

On simplifying;

First we need to note that i² = -1 and √-1 = i

Substituting the values in the expression, it becomes;

= √16(√-1)-√(-3)(-3)-√(-4)(-4)+3i-3(-1)+3i(i²)

= 4i-√9-√16+3i+3-3i

= 4i-3-4+3

= 4i-4

= 4(i-1)

6 0
4 years ago
Manuel found a wrecked 1970 Trans-Am that he could fix. He bought the car for 65% of the original
Paha777 [63]

Answer:

$11077

Step-by-step explanation:

There ya go.

6 0
4 years ago
Use elimination to solve the system of equations
Phantasy [73]

Answer:

A (-5,2)

Step-by-step explanation:

5x+y=-23

7x-3y=-41

3×(5x+y)=3×(-23)

15x+3y=-69

<u>+</u><u>7x-3y</u><u>=</u><u>-41</u>

<u>22x</u>=<u>-110</u>

22. 22

x=-5

5x+y=-23

5(-5)+y=-23

-25+y=-23

<u>+25</u><u>.</u> <u>+25</u>

y=2

When using elimination you add both equations together so that one variable cancels out the other. In this situation, y can be the variable. You must get the y-variables to cancel out leaving just the x- variables to solve for.

6 0
3 years ago
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