Question

Between 10pm and 7:45am, the water level in a swimming pool decreased by 3/8 in. Assuming that the water decreased at a constant rate, how much did the water level drop each hour?

Answer 1

Answer:

$\frac{1}{26}$ inches

Step-by-step explanation:

In order to solve this problem, we need to create a ratio.

Since we're looking for the rate per hour, we need to find how long it is from 10pm to 7:45am.

10pm + 2 hours = 12 AM

12 AM + 7.75 hours = 7:45 AM

So in total, it's 9.75 hours.

$\frac{3}{8}$ is the same as 0.375.

Our fraction will become $\frac{0.375}{9.75}$, which can simplify down to $\frac{1}{26}$.

Now we can create the proportion:

$\frac{1}{26}=\frac{x}{1}$

Now we solve for x by cross multiplying.

$1\cdot1=1\\\\1\div26=\frac{1}{26}$

Hope this helped!