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Agata [3.3K]
3 years ago
11

80% is what fraction of the whole quantity?

Mathematics
1 answer:
USPshnik [31]3 years ago
8 0
The answer is 80/100
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I need help write in line slope-intercept from ​
prisoha [69]

Answer:

Please check the explanation.

Step-by-step explanation:

The equation for the line in slope-intercept form is

y=mx+b

where

  • m is the slope
  • b is the y-intercept

For example, a line of the form y=-3x+2 can be termed as the line of an equation in slope-intercept form after comparing with it.

y=-3x+2

where

  • m=-3
  • y-intercept = b = 2
3 0
2 years ago
Write an expression that shows how to multiply 4 times 362 using place value and expanded form
luda_lava [24]
362=300+60+2\\\\4\times362=4\times(300+60+2)\\\\ues\ distributive\ property:\\\\4\times300+4\times60+4\times2=1200+240+8=\boxed{1448}
3 0
3 years ago
56,927.34 in expanded form
DanielleElmas [232]

Answer:

Step-by-step explanation:

Standard Form:

56,927.34

Expanded forms can be written like a sentence or stacked for readability as they are here.

Expanded Notation Form:

50,000  

+6,000  

+900  

+20  

+7  

+0.3

+0.04

Expanded Factors Form:

 5 ×10,000  

+ 6 ×1,000  

+ 9 ×100  

+ 2 × 0  

+ 7 ×1  

+ 3 ×0.1

+ 4 ×0.01

Expanded Exponential Form:

5 × 104

+ 6 × 103

+ 9 × 102

+ 2 × 101

+ 7 × 100

+ 3 × 10-1

+ 4 × 10-2

5 0
3 years ago
Read 2 more answers
A bag of chocolates is labeled to contain 0.384 pounds of chocolates. The actual weight of the chocolates is 0.3798 pounds. Are
Marta_Voda [28]

Based on the information given the chocolates stated on the label is 0.0042-ounce lighter.

Weight:

Using this formula

Chocolate weight=Current weight-Actual weight

Where:

Current weight=0.384

Actual weight=0.3798

Let plug in the formula

Chocolate weight=0.384-0.3798

Chocolate weight=0.0042 ounce

In conclusion, the chocolates stated on the label are 0.0042-ounce lighter.

6 0
2 years ago
A pizza pan is removed at 9:00 PM from an oven whose temperature is fixed at 450°F into a room that is a constant 70°F. After 5​
gladu [14]

Answer:

A) It will get to a temperature of 125°F at 9:19 PM

B) It will get to a temperature of 150°F at 9:16 PM

C) as time passes temperature approaches the initial temperature of 450°F

Step-by-step explanation:

We are given;

Initial temperature; T_i = 450°F

Room temperature; T_r = 70°F

From Newton's law of cooling, temperature after time (t) is given as;

T(t) = T_r + (T_i - T_r)e^(-kt)

Where k is cooling rate and t is time after the initial temperature.

Now, we are told that After 5​ minutes, the temperature is 300°F.

Thus;

300 = 70 + (450 - 70)e^(-5k)

300 - 70 = 380e^(-5k)

230/380 = e^(-5k)

e^(-5k) = 0.6053

-5k = In 0.6053

-5k = -0.502

k = 0.502/5

k = 0.1004 /min

A) Thus, at temperature of 125°F, we can find the time from;

125 = 70 + (450 - 70)e^(-0.1004t)

125 - 70 = 380e^(-0.1004t)

55/380 = e^(-0.1004t)

In (55/380) = -0.1004t

-0.1004t = -1.9328

t = 1.9328/0.1018

t ≈ 19 minutes

Thus, it will get to a temperature of 125°F at 9:19 PM

B) Thus, at temperature of 150°F, we can find the time from;

150 = 70 + (450 - 70)e^(-0.1004t)

150 - 70 = 380e^(-0.1004t)

80/380 = e^(-0.1004t)

In (80/380) = -0.1004t

-0.1004t = -1.5581

t = 1.5581/0.1004

t ≈ 16 minutes.

Thus, it will get to a temperature of 150°F at 9:16 PM

C) As time passes which means as it approaches to infinity, it means that e^(-kt) gets to 1.

Thus,we have;

T(t) = T_r + (T_i - T_r)

T_r will cancel out to give;

T(t) = T_i

Thus, as time passes temperature approaches the initial temperature of 450°F

6 0
3 years ago
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