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mestny [16]
3 years ago
12

Shiloh has to earn at least $200 to meet her fundraising goal. She has only 100 cakes that she plans to sell at $5 each. Which i

nequality shows the number of cakes, x, Shiloh can sell to meet her goal?
Mathematics
1 answer:
bonufazy [111]3 years ago
4 0

Answer:d

Step-by-step explanation:I took the test too

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Tell whether each scale reduces enlarges or preserves the size of an actual object
mr_godi [17]

Given:

1 m : 25 cm

8 in : 1 ft

12 in : 1 ft

 

First, we convert each variable given on the right:

 

1 m : 0.25 m (this means that 1 meter is made to represent 25 cm)

8 in : 12 feet (this means that 8 in is made to represent 1 feet)

12 in : 12 in (this means that 12 in is made to represent 1 feet)

 

<span>After converting the variables, we can now know if the ratios are enlargement, reduction or preservation. Therefore:

1 m : 25 cm = Enlarge</span>

<span>8 in : 12 feet = Reduce
12 in = 1 ft = Preserve</span>

4 0
3 years ago
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I've tried everywhere to get this answerrrrr ill give brainliest for the correct answer mate!!
kodGreya [7K]

Answer:

What is the question?!?!?

7 0
2 years ago
A certain medical test is known to detect 73% of the people who are afflicted with the disease Y. If 10 people with the disease
Setler [38]

The probability of an event is the measurement of the chance of that event's occurrence. The probabilities of considered events are:

  • P(At least 8 have the disease) ≈ 0.4378
  • P(At most 4 have the disease)  ≈ 0.0342
<h3 /><h3>How to find that a given condition can be modeled by binomial distribution?</h3>

Binomial distributions consist of n independent Bernoulli trials. Bernoulli trials are those trials that end up randomly either on success (with probability p) or on failures( with probability 1- p = q (say))

Suppose we have random variable X pertaining to a binomial distribution with parameters n and p, then it is written as

X = B(n,p)

The probability that out of n trials, there'd be x successes is given by

P(X=x)  = ^nC_xp^x(1-p)^{n-x}

Since 10 people can be either diseased or not and they be so independent of each other (assuming them to be selected randomly) , thus, we can take them being diseased or not as outputs of 10 independent Bernoulli trials.

Let we say

Success= Probability of a diseased person tagged as diseased by the clinic

Failure = Probability of a diseased person tagged as not diseased by the clinic.

Then,

P(Success) = p = 72% = 0.72 (of a single person)

P(Failure) = q = 1-p = 0.28

Let X be the number of people diagnosed diseased by the clinic out of 10 diseased people. Then we have: X ≈ B(n+10,P=0.73)

Calculating the needed probabilities, we get:

a) P(At leased 8 have disease) = P(X≥8) =P(X=8) + P(X=9) + P(X=10)

P(X≥8) = ^{10}C_8(0.73)^8(0.28)^2+^{10}C_9(0.73)^9(0.27)^1+^{10}C_{10}(0.73)^{10}(0.27)^0

P(X≥8) ≈ 0.2548 + 0.1456 + 0.0374 ≈ 0.4378

b)  P(At most 4 have the disease) = P(X≤4) = P(X=0) + P(X=1)+P(X=2)+P(X=3)+P(X=4)

P (X ≤ 4) =

^{10}C_0(0.73)^0(0.27)^{10}+^{10}{C_1(0.73)^1(0.27)^9+^{10}{C_2(0.73)^2(0.27)^8+^{10}C_3(0.73)&^3(0.27)^7 \\

+^{10}C_4(0.73)^4(0.27)^6

P (X ≤ 4) = 0.000003 + 0.000076+0.00088+0.00604+0.02719

P (X ≤ 4) =  0.0342

Thus,

The probabilities of considered events are:

  • P(At leased 8 have disease) = 0.4378 approx
  • P(At most 4 have the disease)  = 0.0342 approx

Learn more about binomial distribution here:

brainly.com/question/13609688

#SPJ1

4 0
2 years ago
Which expression is equivalent to the expression below. 3x+5(x-2).
worty [1.4K]
It would be B) 8x-10. You distribute the 5 to the (x-2) to get 5x-10 and then simplify the expression. 
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3 years ago
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Choose the operation you need to perform first 3 + 5 x 8 ÷ 2
serious [3.7K]

Answer:

Multiplication

Step-by-step explanation:

First multiplication 5x8=40 divided by 2 = 20 add back the three so the equation is now 20+3 =<u>23 The final answer</u>

Go by the order PEMDAS

P-Peretnahesis-there is none so skip this step

E-Exponents-There is none so skip this step

M-Multiplication-and division are mixed so whichever one  comes first you do and then do the multiplication and division operations in the order they go

D-Division & multiplication are mixed so whichever one comes first you do and then do the multiplication and division operations in the order they go.

A-Addition and subtraction are mixed so whichever one  comes first you do and then do the multiplication and division operations in the order they go

S-Subtraction-and addition are mixed so whichever one  comes first you do and then do the multiplication and division operations in the order they go

4 0
1 year ago
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