The first thing to do is find the rectangular warehouse area.
We have then:
A = (12) * (18) = 216
A = 216 m ^ 2
We now look for the area of each acoustic tile square:
A '= (1) ^ 2 = 1
A '= 1 m ^ 2
We look for acoustic tile squares number:
N = (A) / (A ')
N = (216) / (1)
N = 216
Finally we look for the total weight:
W = (1/4) * (216)
W = 54 Kg
Answer:
The total weight of the tile required to cover the ceiling is:
W = 54 Kg
Step-by-step explanation:-
-4y goes on the y axis
and 18 goes on the x axis
4 out of 50 is what percent
4/50 is what percent
percent mens parts out of 100
x%=x/100
4/50=x/100
multiply both sides by 100
8=x
answer is 8%
Hello,
Assume n the number to be found.
n-3 is so a multiple of 8,10,12,30 .
The lcm of 8,10,12,30 is 2^3*3*5=120
n-3=120 or 240 or 360.... n-3=240
==> n=243
