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scoundrel [369]
3 years ago
7

What is the y-intercept of the line shown? −1 0 0.5 1

Mathematics
2 answers:
ad-work [718]3 years ago
3 0
-1, the Y intercept is whatever point the line crosses the Y axsis (the one that goes up and down)
Nuetrik [128]3 years ago
3 0

Answer:

-1

Step-by-step explanation:

It crosses the y axis at negative 1, the y axis is the vertical line

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Please Help!!!<br><br> What is the value of g(−3) when g(x)=2x−2?<br><br> g(−3)= ________
musickatia [10]
G(-3) = 2x - 2      Plug in -3 for x
        = 2(-3) - 2   Multiply
        = -6 - 2       Subtract
        = -8
3 0
3 years ago
In the triangle below, what is the length of the hypotenuse?
aliina [53]

Answer:

<h2>B. 6</h2>

Step-by-step explanation:

I'd like to begin by apologizing for the late reply.

PROCESS:

1) Begin by analyzing the triangle

2) Notice how you can take the sin of 30 to find the hypotenuse

3) sin30= 3/x

4) If you don't see how I did that, a fun trig word play for functions, is

S O/H

C A/H

T O/A

where

S= Sine

C= Cosine

T= Tangent

O= Opposite

H= Hypotenuse

A= Adjacent

so side opposite of 30 is side 3, and the hypotenuse is x.

5) sin30= 3/x = 6

6) Your answer, hypotenuse is 6

BONUS: If you want to find the base length, use Pythagorean theorem.

c=√a2+b2

b=√c2-a2= √6^2 - 3^2= 5.19 or 5.2

7 0
3 years ago
What is the image of the point (-5,-9) after a rotation of 90 degrees counterclockwise about the origin
k0ka [10]

Answer:(9,-5)

Step-by-step explanation: trust me

7 0
3 years ago
PLEASE HELP ME, I DON'T WANNA FAIL PLZZZZZ.
solniwko [45]
The range is the set of all the y or in your case values that g(x) can have

Domain is
X= {0, 1, 2, 3, 4}

Range is
Y= g(x)= { g(0)=3, g(1)=0, g(2)=3, g(3)=12, g(4)=... }
8 0
4 years ago
Find the missing coefficient (4d—4)(3d—2)=12d^2+ []d+8
sergij07 [2.7K]
<span>(4d-4)(3d-2)=12d^2 + []d + 8

Using FOIL method:
4d x 3d = 12d^2
4d x  -2 = -8d
-4 x 3d = -12d
-4 x -2 = 8

Adding common terms, we have:
-8d + -12d = -20 d

The missing coefficient is -20.</span>
8 0
3 years ago
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