3 years ago

each homeroom of reedurban middle school receives 1/12 acre plot of the land shown. how many homerooms receive a plot of land?

Mathematics

1 answer:

Andrei [34K]3 years ago

7 0

I probably did this wrong but i think its 21780.....cause i timed an acre by 1/2 to get that answer <span />

You might be interested in

How many x-intercepts will the graph of y = 3x2 + 6x + 3 have? (Use the discriminant to

KonstantinChe [14]

Answer:

i think D or B is the answer

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The rule of a sequence is 3n+1 write the first five terms

sattari [20]

The 5 term is 4 3n+1

7 0

3 years ago

(2+x)dy/dx=3y need help

den301095 [7]

$(2+x) \frac{dy}{dx} =3y$
$\frac{1}{3y} dy= \frac{1}{2+x} dx$
$\int { \frac{1}{3y} } \, dy = \int { \frac{1}{2+x} } \, dx$
$\frac{1}{3}\ln(3y) = \ln(2+x) + C$
(raise both to the power e): $e^{ \frac{1}{3}\ln(3y)}=e^{\ln(k(2+x))}$
$(3y)^ \frac{1}{3} =k(2+x)$
$3y=k(2+x)^3$
$y= k(2+x)^3$

5 0

2 years ago

Mark owns Siberian Husky sled dogs. He knows from data collected over the years that the weight of the dogs is a normal distribu

kozerog [31]

Calculate the z-score for the given data points in the item using the equation,

z-score = (x - μ) / σ

where x is the data point, μ is the mean, and σ is the standard deviation.

Substituting,
(47.7) z-score = (47.7 - 52.5)/2.4 = -2

This translates to a percentile of 2.28%.

(54.9) z-score = (54.9 - 52.5)/2.4 = 1

This translates to a percentile of 84.13%.

Then, subtract the calculate percentiles to give us the final answer of <em>81.85%.</em>

Thus, 81.85% of the Siberian Husky sled dogs are expected to weigh between 47.7 and 54.9 lbs.

8 0

3 years ago

Consider the following function. F(x)=3/2+4 Using the given function, plot all the ordered pairs for the values in the domain be

Butoxors [25]

I can't edit pictures for you so as a result I can't answer it. But label those numbers on the x line and that will be your answer. And OMG your laptop is torn up I tell you TORN.

8 0

3 years ago