Since in a pass code, the placement of the digits is
important, therefore this means that to solve for the total number of
possibilities we have to make use of the principle of Permutation. The formula
for calculating the total number of possibilities using Permutation is given
as:
P = n! / (n – r)!
where,
n = is the total amount of numbers to choose from = 20
r = is the total number of digits needed in the passcode =
4
Therefore solving for the total possibilities P:
P = 20! / (20 – 4)!
P = 20! / 16!
P = 116,280
<span>Hence there are a total of 116,280 possibilities of pass
codes.</span>
D(2)
C(6)
A(5)
B(4)
https://www.mathsisfun.com/definitions/coefficient.html
Create an inequality
x/60 = 30/100
x = 200
CHECK ANSWER: 200 x .30 = 60
Answer:
1 boy then 1 girl = 48 in 189 probability. 1 boy then 1 boy = 33 in 132 probability
Step-by-step explanation:
1 boy then 1 girl:
12/28 x 16/27
1 boy then 1 boy:
12/28 x 11/27
Simplify the fractions to make it easier.
Answer:
$2
Step-by-step explanation:
x = daylily
y = geranium
1x + 5y = 22
13x + 1y = 30
Multiply second equation by 5 and subtract the two equations.
1x + 5y = 22
- (65x + 5y = 150)
-64x = -128
x = 2
So one daylily costs 2 dollars
