Answer:1)5x^2-11x
2) x^2-3x
Step-by-step explanation:
1)(f+g)(x)
f(x)=3x-7
g(x)= 2x-4
[(3x-7)+(2x-4)](x)
3x^2-7x+2x6^2-4x
=<u>5x^2-11x</u>
2) (f-g)(x)
[(3x-7)-(2x-4)](x)
(3x-7-2x+4)(x)
3x^2-7x-2x^2+4x
x^2-3x
Since he descended 12 meters, we subtract this from the overall height of Mount Ka'ala, so then we are only calculating how high ABOVE the sea level it is.
1232 - 12 = 1220
The height of Mount Ka'ala is therefore 1,220 meters.
To calculate how much a fifth of Mount Ka'ala is (since the ranger station is 2/5's up), we would divide this number by 5
1220 ÷ 5 = 244
Since ONE fifth of the height is 244 meters, TWO fifths would be double that amount.
244 x 2 = 488
488 meters.
The ranger station is 488m above sea level.
Answer:

.
Step-by-step explanation:
Use the form below

Where
is a slope
and
are the point of the line
.
So, the slope is


.





.
Happy to help:)
I think that the answer is A.