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Kaylis [27]
3 years ago
6

A line passes through (-7, -5) and (-5, 4). a. Write an equation gor the line in point-slope form. b. Rewrite the equation in st

andard form using integers.
A. Y-5=9/2(x+7);-9x+2u=-53
B. Y+5=9/2(x-7);-9x+2y=53
C. Y+5=9/2(x+7);-9x+2y=53
D. Y+7=9/2(x+5);-9x+2y=31
Mathematics
1 answer:
Vadim26 [7]3 years ago
6 0
\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ -7 &,& -5~) 
%  (c,d)
&&(~ -5 &,& 4~)
\end{array}
\\\\\\
% slope  = m
slope =  m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{4-(-5)}{-5-(-7)}\implies \cfrac{4+5}{-5+7}\implies \cfrac{9}{2}

\bf \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-5)=\cfrac{9}{2}[x-(-7)]
\\\\\\
\boxed{y+5=\cfrac{9}{2}(x+7)}\implies y+5=\cfrac{9}{2}x+\cfrac{63}{2}\impliedby 
\begin{array}{llll}
\textit{and now we multiply}\\
\textit{both sides by }\stackrel{LCD}{2}
\end{array}
\\\\\\
2y+10=9x+63\implies \boxed{\stackrel{\textit{standard form}}{-9x+2y=53}}

just a quick note, multiplying both sides by the LCD, whatever it may be, simply gets rid of the denominators.
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3 years ago
What is the slope of the line that passes through the pair of points (1/3, -1) and ( -2, 9/2)​
UkoKoshka [18]

Answer:

\boxed{m = - \frac{33}{14} }

.

Step-by-step explanation:

Use the form below

\boxed{\boxed{m = \frac{y_2 - y_1}{x_2 - x_1} }}

Where

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  • (x_1,~y_1) and (x_2,~y_2) are the point of the line

.

So, the slope is

(\frac{1}{3} ,~ -1) \to x_1 = \frac{1}{3} ~and~y_1 = -1

(-2,~ \frac{9}{2} ) \to x_2 = -2~and~y_2 = \frac{9}{2}

.

m = \frac{\frac{9}{2} -(-1)}{-2-\frac{1}{3} }

m = \frac{\frac{11}{2} }{\frac{-7}{3} }

m = \frac{11}{2} \div (-\frac{7}{3} )

m = \frac{11}{2} \times (-\frac{3}{7} )

m = - \frac{33}{14}

.

Happy to help:)

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3 years ago
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alukav5142 [94]
I think that the answer is A.
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