Answer:
none of the above? sorry not too sure
Answer:
y = -x/6 + 2
Step-by-step explanation:
To solve this problem, we will subtract the volume of the cylinder from the volume of the rectangular prism.
The volume of a cylinder is: pi*r^2*h
Substitute 2 in for r and 6 in for h. If the diameter is 4, then the radius is 2.
pi*2^2*6
pi*4*6
pi*24
=75.4 ft^2
The volume of the rectangular prism is: l*w*h.
Substitute 6 in for l, w and h, since all edges are equal.
6*6*6
36*6
=216 ft^2
Subtract 75.4 from 216
216-75.4=140.6
There is 140.6 cubic feet of concrete left in the block.
Answer:
3.5 hours
Step-by-step explanation:
Ediburgh -------------------------------350 miles-------------------------London
Let the distance traveled by train from Edin to London be "x"
hence the distance traveled by train from London to Edin would be "350-x"
- The rate of Edin to London train is 60
- The rate of London to Edin train is 40
Let the time they meet be"t"
Now, we know distance formula to be D = RT
Where
D is distance
R is rate
and
T is time
<u>Train from Edin to London:</u>
x = 60t
<u>Train from London to Edin:</u>
350-x = 40t
Solving for x:
350 - 40t = x
We put this into first equation:
x = 60t
350 - 40t = 60t
350 = 100t
t = 350/100
t = 3.5
They meet after 3.5 hours
Answer:
There are two possibilities:
and 
and 
Step-by-step explanation:
Mathematically speaking, the statement is equivalent to this 2-variable non-linear system:


First,
is cleared in the first equation:

Now, the variable is substituted in the second one:

And some algebra is done in order to simplify the expression:


Roots are found by means of the General Equation for Second-Order Polynomials:
and 
There are two different values for
:






There are two possibilities:
and 
and 