Question

In ΔTUV, the measure of ∠V=90°, the measure of ∠U=85°, and VT = 20 feet. Find the length of TU to the nearest tenth of a foot.

Answer 1

Answer: 20.1

Step-by-step explanation:

sinU=  

hypotenuse

opposite

​  

=  

x

20

​  

 

\sin 85=\frac{20}{x}

sin85=  

x

20

​  

 

x\sin 85=20

xsin85=20

Cross multiply.

\frac{x\sin 85}{\sin 85}=\frac{20}{\sin 85}

sin85

xsin85

​  

=  

sin85

20

​  

 

Divide each side by sin 85.

x=\frac{20}{\sin 85}=20.0764\approx 20.1\text{ feet}

x=  

sin85

20

​  

=20.0764≈20.1 feet

Type into calculator and roundto the nearest tenth of a foot.

T

U

V

20

20.1

(opposite of ∠U)

(adj. to ∠U)

(hypotenuse)

85°

Answer 2

Answer: 20.1

Step-by-step explanation: I if you are here from delta math this is the answer