um time de futsal marcou 60 gols, correspondendo a quatro sextos do total de gols do campeonato. Quantos gols foram marcados no
1 answer:
Answer:
<h2>The team scored a total of 90 goals.</h2>Step-by-step explanation:
The given question is
<em>A futsal team scored 60 goals, corresponding to four-sixths of the league's total goals. How many goals were scored in the league?</em>
<em />
If 60 goals represents four-sixths of the total goals, then how many goals were scored?
Here we need to use the rule of three, where the given equivalence is
And the total number of goals is represents by 1, which is the 100% of goals.
Therefore, the team scored a total of 90 goals.
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Answer:
0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean 490 mg and variance of 400.
This means that
What is the probability that a randomly selected pill contains at least 500 mg of minerals?
This is 1 subtracted by the p-value of Z when X = 500. So
has a p-value of 0.6915.
1 - 0.6915 = 0.3085
0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals