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ValentinkaMS [17]
3 years ago
13

um time de futsal marcou 60 gols, correspondendo a quatro sextos do total de gols do campeonato. Quantos gols foram marcados no

campeonato?
Mathematics
1 answer:
artcher [175]3 years ago
6 0

Answer:

<h2>The team scored a total of 90 goals.</h2>

Step-by-step explanation:

The given question is

<em>A futsal team scored 60 goals, corresponding to four-sixths of the league's total goals. How many goals were scored in the league?</em>

<em />

If 60 goals represents four-sixths of the total goals, then how many goals were scored?

Here we need to use the rule of three, where the given equivalence is

60 \ goals = \frac{4}{6}

And the total number of goals is represents by 1, which is the 100% of goals.

x=1\frac{60 \ goals}{\frac{4}{6} }=\frac{360}{4} \ goals\\  x=90

Therefore, the team scored a total of 90 goals.

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If L, M and N are midpoints of the sides of PQR, PR = 46, PQ = 40, and LN=17, find each measure
Serga [27]

Check the picture below.

let's recall that the midsegment of a triangle is the segment that's half-way to both endsides and is at the same time parallel to the 3rd side, is also half the length of the parallel side, so-called the base.

so, for example, we know L, M and N are midpoints to each segment, that means that LM is a midsegment and parallel to PR and also half the length of PR, same is true for LN and MN.

5 0
2 years ago
6:
horrorfan [7]

Step-by-step explanation:

charging the phone for 1 minute ,it has 2%

i.e,1----->2

After 2 minutes from that time ,i.e total 3 minutes

it has 6% charge

i.e,3--------->6

from the both the above cases ,1 minute provide 2%=6/3

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Hence,

for getting 50%charge=50/2

=25 min

and,for 90 %charge=90\2

=45 min

8 0
2 years ago
Maria studied the traffic trends in India. She found that the number of cars on the road increases by 10% each year. If there we
lord [1]

Answer:

b. 8,800,000.

Step-by-step explanation:

In maria study the number of cars on the road increases by 10% each year.

Total number of cars in the first year =80 million cars.

We will add 10% of 80 million to 80 milion to enable us get the number of cars for the second year.

For year 2 we have;

10% of 80,000,000+80,000,000

\frac{10}{100}*80,000,000+80,000,000

8,000,000 + 80,000,000

88,000,000

number of cars in year 2 = 88 million

We will add 10% of 88 million to 88 milion to enable us get the number of cars for the third year.

\frac{10}{100}*88,000,000+88,000,000

8,800,000+88,000,000

96,800,000

the number of cars on the road in year 3 compared to year 2 will just be the increase which is in BOLD. That is 8,800,000

<em>or simply subtract the number of cars in year 2 from that in year 3;</em>

96,800,000-88,000,000 = 8,800,000

8 0
3 years ago
Read 2 more answers
Please help with this question i will mark you brainliest!
adell [148]

9514 1404 393

Answer:

  equation: y = 4x

  graph is attached

Step-by-step explanation:

Let y represent the cost of the peaches in dollars. Let x represent their weight in pounds. Then the relation between the two variables is ...

  cost = (cost per pound) × (pounds)

  y = 4x

__

This graphs as a line through the origin with a slope of 4. In the attached, the x- and y-axes have different scales so more of the graph can be seen.

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3 years ago
Find the volume of the following cone. Use 3.14 for n and
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28 m because it is the smallest number
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