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2 years ago

Y = 8x + 10 y = 2 whats the substitution ?

Mathematics

1 answer:

viva [34]2 years ago

3 0

Answer:

Look at the explanation.

I'll be online so let me know if you still need help.

Step-by-step explanation.

A system of equations is basically two or more equations that rely on each other. If a solution for a variable is 2, it has to work for the other equation.

The substitution is basically plugging in the y value to y = 8x + 10

If y = 2

and also y = 8x + 10

What do you think the substitution is?

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Which fractions have a least common denominator of 36?

lutik1710 [3]

Answer:

The answer is a =3/4 and 5/18

Step-by-step explanation:

5 0

2 years ago

During the 7th examination of the Offspring cohort in the Framingham Heart Study, there were 1219 participants being treated for

AlexFokin [52]

Answer:

95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

Step-by-step explanation:

We are given that during the 7th examination of the Offspring cohort in the Framing ham Heart Study, there were 1219 participants being treated for hypertension and 2,313 who were not on treatment.

The sample proportion is : $\hat p$ = x/n = 1219/3532 = 0.345

Firstly, the pivotal quantity for 95% confidence interval for the proportion of the population is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion = 0.345

n = sample of participants = 3532

p = population proportion

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level of

significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p= [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.345-1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } }$ , $0.345+1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } }$ ]

= [0.3293 , 0.3607]

Hence, 95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

6 0

3 years ago

3x-12+10=8-2x what does x equal?

nikitadnepr [17]

X=2 because first you have to combine like terms. Than you have to bring the Varible on one side. Finally you solve for the Varible and you get the answer2.

5 0

3 years ago

Read 2 more answers

Y= -0.25x + 4.7 Y=4.9x - 1.64

Andreas93 [3]

Answer:

The answer would be (1.23, 4.39)

Step-by-step explanation:

Because they are both equal to y, we can set the equations equal to each other and then solve.

4.9x - 1.64 = -0.25x + 4.7

5.15x - 1.64 = 4.7

5.15x = 6.34

x = 1.23

Now that we have the value for x, we can plug into either equation and find y.

y = -0.25x + 4.7

y = -0.25(1.23) + 4.7

y = -.31 + 4.7

y = 4.39

3 0

3 years ago

How does a digit in the ten thousands place compare to a digit in the thousands place?

svetlana [45]

The digits in the ten-thousands place is 10,000 times the value of a digit, right? For example, 10,000 is 10,000 times 1, and one is a mere digit. The thousands place follows the same rule, with 1,000 being 1,000 times 1. Ergo, when compared, you could think of it as 10,000/1,000 = 10. We can think of this as a digit in the ten-thousands place is 10 times the value of the same digit in the thousands place.

8 0

3 years ago