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2 years ago

Which expression makes the equation true?

1 answer:

N76 [4]2 years ago

8 0

1. C.

The rule of powers is that when a parenthesis is raised to a power, you multiply the two numbers. Since it is being raised to the second power, it needs to have a 10 in the parenthesis. That would make 20.

2. B

Firstly 10^2 = 100, so we know that the number must be 10. That leaves us with just A and B. Then we know the same thing from the previous equation, that they need to be multiplied together.

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Evaluate the integral. W (x2 y2) dx dy dz; W is the pyramid with top vertex at (0, 0, 1) and base vertices at (0, 0, 0), (1, 0,

In-s [12.5K]

Answer:

$\mathbf{\iiint_W (x^2+y^2) \ dx \ dy \ dz = \dfrac{2}{15}}$

Step-by-step explanation:

Given that:

$\iiint_W (x^2+y^2) \ dx \ dy \ dz$

where;

the top vertex = (0,0,1) and the base vertices at (0, 0, 0), (1, 0, 0), (0, 1, 0), and (1, 1, 0)

As such , the region of the bounds of the pyramid is: (0 ≤ x ≤ 1-z, 0 ≤ y ≤ 1-z, 0 ≤ z ≤ 1)

$\iiint_W (x^2+y^2) \ dx \ dy \ dz = \int ^1_0 \int ^{1-z}_0 \int ^{1-z}_0 (x^2+y^2) \ dx \ dy \ dz$

$\iiint_W (x^2+y^2) \ dx \ dy \ dz = \int ^1_0 \int ^{1-z}_0 ( \dfrac{(1-z)^3}{3}+ (1-z)y^2) dy \ dz$

$\iiint_W (x^2+y^2) \ dx \ dy \ dz = \int ^1_0 \ dz \ ( \dfrac{(1-z)^3}{3} \ y + \dfrac {(1-z)y^3)}{3}] ^{1-x}_{0}$

$\iiint_W (x^2+y^2) \ dx \ dy \ dz = \int ^1_0 \ dz \ ( \dfrac{(1-z)^4}{3}+ \dfrac{(1-z)^4}{3}) \ dz$

$\iiint_W (x^2+y^2) \ dx \ dy \ dz =\dfrac{2}{3} \int^1_0 (1-z)^4 \ dz$

$\iiint_W (x^2+y^2) \ dx \ dy \ dz =- \dfrac{2}{15}(1-z)^5|^1_0$

$\mathbf{\iiint_W (x^2+y^2) \ dx \ dy \ dz = \dfrac{2}{15}}$

7 0

2 years ago

4x + 1 = 2x – 5 can someone help me. Whoever gets it right gets it right gets brainliest

castortr0y [4]

Answer:

x=-3

Step-by-step explanation:

subtract "2x" to "4x + 1" and that'll leave -5 by itself and leave 2x+1 on the left and -5 on the right then subtract -1 to -5 and it'll add up to -6 then after that you'd divide 2x to -6 and get -3 and it'll leave 'x' by itself so therefore X = -3

3 0

2 years ago

Read 2 more answers

8. The equation at the right has been incorrectly solved.

ozzi

The equation at the right has been incorrectly solved, the answer to this is b = -7

8 0

1 year ago

Read 2 more answers

Is 16% of 40 the same as 40% of 60? Explain your reasoning.

o-na [289]

No 16% of 40 is 32/5 where 40%of 60 is 24.
Hope this helps.

6 0

2 years ago

Read 2 more answers

A sum of two mixed numbers is given.<br><br> What is the missing number?

kaheart [24]

Answer:

16.

Step-by-step explanation:

The whole numbers stay the same so it stays as 2. The way they get 30 for the denominator is by multiplying the fraction 1/3 by 10 and 1/5 by 6. So now we have 10/30 and 6/30. Add them together, 10+6=16

4 0

2 years ago