The global maxima is at what point? A. c B. b C. a and b D. a

tresset_1 [31]

Answer:
(5 * 1) + (9 * 0.1).

Explanation:
To write a number in expanded form you have each digit multiplied by its numbers place and add each digit together. 5 is in the ones place so it becomes (5 * 1).
9 is in the tenths place so it becomes (9 * 0.1).
add them together to get (5 * 1) + (9 * 0.1)

3 0

3 years ago

Read 2 more answers

Find the value of x. Round to the nearest tenth.

nordsb [41]

Step-by-step explanation:

here,,

a=3,b=10,C=120°

c^2=a^2+b^2-2ab cos120°

=(3)^2 +(10)^2 _2 (3)(10)(-1/2) [cos120°=-1/2]

=9+100-(-30)

=109+30

=139

c=(139 )1/2=11.79

c=12

3 0

3 years ago

Given a triangle ABC at A = ( - 1, 3 ) B = ( 1, - 1 ) C = ( 2, 2 ) and if the triangle is rotated 90 ° clockwise about the point

lidiya [134]

Answer:

The coordinates of A' are (6,6).

Step-by-step explanation:

It is given that in triangle ABC, A = (-1, 3), B = (1, - 1) and C = (2, 2).

If a point is rotated 90 ° clockwise about the point ( a,b ), then

$(x,y)\rightarrow ((y-b)+a,-(x-a)+b)$

It is given that the triangle is rotated 90 ° clockwise about the point ( 4, 1 ). So, a=4 and b=1.

$(x,y)\rightarrow ((y-1)+4,-(x-4)+1)$

$(x,y)\rightarrow (y+3,-x+5)$

The coordinates of A are (-1,3), So, the coordinates of A' are

$A(-1,3)\rightarrow A'(3+3,-(-1)+5)$

$A(-1,3)\rightarrow A'(6,6)$

Therefore the coordinates of A' are (6,6).

7 0

3 years ago

Find the area of a polygon with the given vertices A(2,2) B(5,2) C(3,-1) D(0,-1) Number 21

Bogdan [553]

Answer:

Je pense que je ne sais pas vraiment

6 0

3 years ago

) One year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million. Suppose a samp

Nutka1998 [239]

Answer:

Probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.

Step-by-step explanation:

We are given that one year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million.

Suppose a sample of 400 major league players was taken.

Let $\bar X$ = sample average salary

The z-score probability distribution for sample mean is given by;

Z = $\frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} }$ ~ N(0,1)

where, $\mu$ = mean salary = $1.5 million

$\sigma$ = standard deviation = $0.9 million

n = sample of players = 400

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the average salary of the 400 players exceeded $1.1 million is given by = P( $\bar X$ > $1.1 million)

P( $\bar X$ > $1.1 million) = P( $\frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} }$ > $\frac{ 1.1-1.5}{{\frac{0.9}{\sqrt{400} } }} }$ ) = P(Z > -8.89) = P(Z < 8.89)

Now, in the z table the maximum value of which probability area is given is for critical value of x = 4.40 as 0.99999. So, we can assume that the above probability also has an area of 0.99999 or nearly close to 1.

Therefore, probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.

4 0

3 years ago