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nikdorinn [45]
3 years ago
15

When you are trying to find the endpoint when given the midpoint and one point, what would the new formula be? Manipulate the fo

rmula using skills for solving literal equations. How would you find LaTeX: x_2\:\:\:or\:\:\:y_2x 2 o r y 2? Use LaTeX: x_m\:\:and\:\:\:\:y_mx m a n d y mto notate the midpoints. Remember the original midpoint formula is LaTeX: \left(\frac{x_1+\:x_2}{2},\:\:\frac{y_{1\:}+y_2}{2}\right)\:=\:\left(x_m,\:y_m\right)
Mathematics
1 answer:
MariettaO [177]3 years ago
7 0

Answer:

(x_2,y_2) = (2x_m - x_1 ,2y_m - y_1 )

Step-by-step explanation:

Given

\left(\frac{x_1+\:x_2}{2},\:\:\frac{y_{1\:}+y_2}{2}\right)\:=\:\left(x_m,\:y_m\right)

Required

Determine x2, y2

Start by splitting the expression

x_m = \left(\frac{x_1+\:x_2}{2}) and y_m = (\frac{y_{1\:}+y_2}{2})

Solving for x2 in x_m = \left(\frac{x_1+\:x_2}{2})

Multiply through by 2

2 * x_m = \frac{x_1 + x_2}{2} * 2

2x_m = x_1 + x_2

Make x2 the subject;

x_2 = 2x_m - x_1

Similarly:

y_m = (\frac{y_{1\:}+y_2}{2})

Multiply through by 2

2 * y_m = \frac{y_1 + y_2}{2} * 2

2y_m = y_1 + y_2

Make y2 the subject;

y_2 = 2y_m - y_1

Hence:

(x_2,y_2) = (2x_m - x_1 ,2y_m - y_1 )

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Lyle bought a baseball card for $800. If the value of the card decreases by 1.5% each year, find the value of the card after 12
allsm [11]

Answer:

FV= $669.11

Step-by-step explanation:

Giving the following information:

Purchase price (PV)= $800

Decrease value (d)= 1.5% per year

Number of periods (n)= 12 years

<u>To calculate the value of the card after 12 years, we need to use the following formula:</u>

FV= PV / (1 + d)^n

FV= 800 / (1.015^12)

FV= $669.11

6 0
3 years ago
If the gradient of the tangent to
Marizza181 [45]

Answer:

Point A(9, 3)

General Formulas and Concepts:

<u>Pre-Algebra</u>  

Order of Operations: BPEMDAS  

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties  

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>  

  • Coordinates (x, y)
  • Functions
  • Function Notation
  • Terms/Coefficients
  • Anything to the 0th power is 1
  • Exponential Rule [Rewrite]:                                                                              \displaystyle b^{-m} = \frac{1}{b^m}
  • Exponential Rule [Root Rewrite]:                                                                     \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}  

<u>Calculus</u>  

Derivatives  

Derivative Notation  

Derivative of a constant is 0  

Basic Power Rule:  

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                    \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle y = \sqrt{x}<em />

<em />\displaystyle y' = \frac{1}{6}<em />

<em />

<u>Step 2: Differentiate</u>

  1. [Function] Rewrite [Exponential Rule - Root Rewrite]:                                   \displaystyle y = x^{\frac{1}{2}}
  2. Basic Power Rule:                                                                                             \displaystyle y' = \frac{1}{2}x^{\frac{1}{2} - 1}
  3. Simplify:                                                                                                             \displaystyle y' = \frac{1}{2}x^{-\frac{1}{2}}
  4. [Derivative] Rewrite [Exponential Rule - Rewrite]:                                          \displaystyle y' = \frac{1}{2x^{\frac{1}{2}}}
  5. [Derivative] Rewrite [Exponential Rule - Root Rewrite]:                                 \displaystyle y' = \frac{1}{2\sqrt{x}}

<u>Step 3: Solve</u>

<em>Find coordinates of A.</em>

<em />

<em>x-coordinate</em>

  1. Substitute in <em>y'</em> [Derivative]:                                                                             \displaystyle \frac{1}{6} = \frac{1}{2\sqrt{x}}
  2. [Multiplication Property of Equality] Multiply 2 on both sides:                      \displaystyle \frac{1}{3} = \frac{1}{\sqrt{x}}
  3. [Multiplication Property of Equality] Cross-multiply:                                      \displaystyle \sqrt{x} = 3
  4. [Equality Property] Square both sides:                                                           \displaystyle x = 9

<em>y-coordinate</em>

  1. Substitute in <em>x</em> [Function]:                                                                                \displaystyle y = \sqrt{9}
  2. [√Radical] Evaluate:                                                                                         \displaystyle y = 3

∴ Coordinates of A is (9, 3).

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

7 0
3 years ago
M is a degree 3 polynomial with m ( 0 ) = 53.12 and zeros − 4 and 4 i . Find an equation for m with only real coefficients (i.E.
Nitella [24]

Answer:

Therefore the required polynomial is

M(x)=0.83(x³+4x²+16x+64)

Step-by-step explanation:

Given that M is a polynomial of degree 3.

So, it has three zeros.

Let the polynomial be

M(x) =a(x-p)(x-q)(x-r)

The two zeros of the polynomial are -4 and 4i.

Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.

Then,

M(x)= a{x-(-4)}(x-4i){x-(-4i)}

      =a(x+4)(x-4i)(x+4i)

      =a(x+4){x²-(4i)²}      [ applying the formula (a+b)(a-b)=a²-b²]

      =a(x+4)(x²-16i²)

      =a(x+4)(x²+16)      [∵i² = -1]

      =a(x³+4x²+16x+64)

Again given that M(0)= 53.12 . Putting x=0 in the polynomial

53.12 =a(0+4.0+16.0+64)

\Rightarrow a = \frac{53.12}{64}

      =0.83

Therefore the required polynomial is

M(x)=0.83(x³+4x²+16x+64)

5 0
3 years ago
A water storage tank is in the shape of a cone with the pointed end down. If the radius is 21 feet and the depth of the tank is
andre [41]

The volume of the water storage tank is the amount of space in it

The volume of the water storage tank is 6468 cubic feet

<h3>How to determine the volume?</h3>

The given parameters are:

Radius (r) = 21 feet

Height (h) = 14 feet

The shape of the water storage tank is a cone.

And the volume of a cone is:

V = 1/3πr^2h

So, we have:

V = 1/3 * 22/7 * 21^2 * 14

This gives

V = 6468

Hence, the volume of the water storage tank is 6468 cubic feet

Read more about volumes at:

brainly.com/question/1972490

4 0
2 years ago
Jodie invests $12,000 in a savings account that pays 2% simple interest. How many years will it take for the account to grow to
Butoxors [25]

Answer:

4 years

Step-by-step explanation:

5 0
2 years ago
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