hi!
so the original equation is (x^2 -121) / x+ 11.
Those two equations look similar...
well, we know that the top equation looks like a^2 - b^2, and that equation iis equivalent to this equation: (a+b)(a-b).
So if we factor that out, we get:
( (x + 11) * (x-11) )/ (x + 11)
we can cancel the x+11 on the top and the x+11 on the bottom out.
that leaves us with x-11.
Hope this helped!
Answer:
Sry if it is wrong..........
For question 4: you have to do (y2 - y1) divided by (x2 - x1) to get the rise over run...
5-2
——. = 3/4
11 - 7
For question 5: input the values of x,y and the gradient into the equation of a line.....
y = mx+ c
-8 = 3(-2) + c
-8 = -6 + c
-2 = c
therefore:
y = 3x - 2
Hope this helps! Any questions let me know :)
Answer:The correct answer is 2/3x + 17
Step-by-step explanation:
