Question

In Exercises 15 and 16, tell whether the triangle with the given side

Answer 1

15. 10 cm, 10 cm, V200 cm  : Right Angled Triangle

16. 9 in., 16 in., 25 in. : Not a right angled triangle

Step-by-step explanation:

In order to check whether the given sides form a right angled triangle, we check if the sum of squares of two shorter sides is equal to the square of third longest side.

So

15. 10 cm, 10 cm, V200 cm

$The\ shorter\ sides\ are\ 10cm\ and\ 10cm\\Let \\a=10\\b=10\\c=\sqrt{200}So,\\c^2=a^2+b^2\\(\sqrt{200})^2=(10)^2+(10)^2\\200 = 100+100\\200 = 200$

The triangle is a right angled triangle.

16. 9 in., 16 in., 25 in.​

Here

a = 9 in

b=16 in

c=25 in

So,

$c^2=a^2+b^2\\(25)^2=(9)^2+(16)^2\\625=81+256\\625=337$

The given triangle is not a right angled triangle.

Keywords: Triangle, Right angled Triangle

Learn more about triangle at:

• brainly.com/question/12896802
• brainly.com/question/12973601

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