Question

Solve this system of equations: y = x2 – 3x + 12 y = –2x + 14 1.Isolate one variable in the system of equations, if needed. y = x2 – 3x + 12 y = –2x + 14 2.Use substitution to create a one-variable equation. –2x + 14 = x2 – 3x + 12 3.Solve to determine the unknown variable in the equation. What are the values of x?

Answer 1

-2x+14=x²-3x+12
add 2x on both side:
14=x²-x+12
subtract 14 on both side:
x²-x-2=0
factor: (x-2)(x+1)=0
x=2 or x=-1
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Answer 2

The resulting equation will be

x^2 - x - 2 =0
x^2 -2x +x -2 = 0
(x-2)(x+1) = 0
x= 2 and x = -1

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