Answer:
∫ = ㏑|x| +c
Proof:
let x = take derivative for both sides
so dx = * du
substitute in the original function
∫du = u + C
u = ㏑|x|
Write an equation of the line perpendicular to the given line that contains P.
2 answers:
Answer:
y +5 = -1/3(x -3)
Step-by-step explanation:
The slope of the given line is 3. The slope of the perpendicular line is the negative reciprocal of that, -1/3. Then the point-slope equation is ...
y -y1 = m(x -x1) . . . . line with slope m through point (x1, y1)
y -(-5) = -1/3(x -3)
y +5 = -1/3(x -3)
You might be interested in