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Elan Coil [88]
2 years ago
7

In 1955 an antique car that originally cost 3,943 is valued at 64,125 if in excellent condition, winch is 2 1/4 times as much as

a car in very nice condition,if you find an owner willing to part with one for any price.What would be the value of thw car in very nice condition
Mathematics
1 answer:
nika2105 [10]2 years ago
7 0

Answer:

The value of the car in very nice condition is $28,500.

Step-by-step explanation:

Consider the provided information.

In 1955 an antique car that originally cost 3,943 is valued at 64,125 if in excellent condition, winch is 2 1/4 times as much as a car in very nice condition.

The mixed fraction can be written as:

2 \frac{1}{4}=\frac{9}{4}

Let x is the value of car in very nice condition.

64,125 =\frac{9}{4}x

x=\frac{64,125\times 4}{9}

x=28,500

Hence, the value of the car in very nice condition is $28,500.

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The radius of a. circular garden is 15 feet. About how much fencing will be needed to enclose the garden?
WINSTONCH [101]

Answer:

94.2 ft of fencing

Step-by-step explanation:

To answer this, find the circumference, C, of the garden, using the circumference formula C = 2(pi)r.

Here, with r = 15 ft, we get C = 2(3.14)(15 ft) = 94.2 ft of fencing will enclose this garden.

8 0
2 years ago
What does this equal 4x+27=3x
EastWind [94]

Answer:

-27 = x

Step-by-step explanation:

4x+27=3x

Subtract 4x from each side

4x-4x+27=3x-4x

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Multiply by -1

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5 0
3 years ago
Read 2 more answers
Joelle ordered 12 dozen doughnuts for the honor roll
Serjik [45]

Answer:

The answer is there are 30 glazed donuts

Step-by-step explanation:

there are 12 donuts to a dozen therefore 12 * 12 = 144 donuts all together.

donuts with chocolate icing

144 \times  \frac{3}{8}  = 54

with white icing and sprinkles

144 \times \frac{1}{4}  = 36

donuts with pink icing

144 \times  \frac{1}{6}  = 24

Total donuts minus donuts with icing equal glazed donuts

144 - 54 - 36 - 24 = 30

7 0
2 years ago
The defect length of a corrosion defect in a pressurized steel pipe is normally distributed with mean value 30 mm and standard d
skelet666 [1.2K]

Answer:

z=-0.842

And if we solve for a we got

a=30 -0.842*7.8=23.432

So the value of height that separates the bottom 20% of data from the top 80% is 23.432.  

Step-by-step explanation:

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(30,7.8)  

Where \mu=30 and \sigma=7.8

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.80   (a)

P(X   (b)

As we can see on the figure attached the z value that satisfy the condition with 0.20 of the area on the left and 0.80 of the area on the right it's z=-0.842

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.842

And if we solve for a we got

a=30 -0.842*7.8=23.432

So the value of height that separates the bottom 20% of data from the top 80% is 23.432.  

8 0
3 years ago
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