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vichka [17]
3 years ago
8

Carey is trying to decide between two guitars. The first had an original price of $160, but is on sale for $100. The second had

an original price of $250, but is on sale for $150. Which guitar has a greater percent change in price?
Mathematics
2 answers:
sasho [114]3 years ago
6 0

the one on sale for $100 would be the better buy for the guitar

tensa zangetsu [6.8K]3 years ago
3 0

Answer:

the second option has a greater change in price 40%

Step-by-step explanation:

Hello , Let me help you with this

to solve this  you can find the percent change in price for every guitar using a simple rule of three.

Step 1

The first had an original price of $160, but is on sale for $100.

if

$160 ⇒ 100%

$100   ⇒x?

the relation is

\frac{160}{100}=\frac{100}{x}\\solve\ for\ x\\\frac{x*160}{100}=100\\x*160=100*100\\x=\frac{100*100}{160} \\x=62.5

the discount will be

100%-62.5%=37.5%

the discount is 37.5%

Step 2

The first had an original price of $250, but is on sale for $150

if

$250 ⇒ 100%

$150   ⇒x?

the relation is

\frac{250}{100}=\frac{150}{x}\\solve\ for\ x\\\frac{x*250}{100}=150\\x*250=150*100\\x=\frac{150*100}{250} \\x=60

the discount will be

100%-60=40%

the discount is 40%

the second option has a greater change in price 40%

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Step-by-step explanation:

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<em><u>SUCCESSOR</u></em>

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Step-by-step explanation:

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The formula to solve a quadratic equation of the form ax^2 + bx + c = 0 is equal to x = [-b +/-√(b^2 - 4ac)]/2a

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x = [-11 +/- √(11^2 - 4(2)(-63))]2(2)

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x = [-11 +/- √625]/4

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3 years ago
Read 2 more answers
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