Answer:
•cos(s+t) = cos(s)cos(t) - sin(s)sin(t) = (-⅖).(-⅗) - (√21 /5).(⅘) = +6/25 - 4√21 /25 = (6-4√21)/25
•cos(s-t) = cos(s)cos(t) + sin(s)sin(t) = (-⅖).(-⅗) + (√21 /5).(⅘) = +6/25 + 4√21 /25 = (6+4√21)/25
cos(t) = ±√(1 - sin²(t)) → -√(1 - sin²(t)) = -√(1 - (⅘)²) = -⅗
sin(s) = ±√(1 - cos²(s)) → +√(1- cos²(s)) = +√(1 - (-⅖)²) = √21 /5
Answer:
f(x) and g(x) are inverse functions
Step-by-step explanation:
In the two functions f(x) and g(x) if, f(g(x)) = g(f(x)) = x, then
f(x) and g(x) are inverse functions
Let us use this rule to solve the question
∵ f(x) = 3x²
∵ g(x) = 
→ Find f(g(x)) by substitute x in f(x) by g(x)
∴ f(g(x)) = 3(
)²
→ Cancel the square root with power 2
∴ f(g(x)) = 3(
)
→ Cancel the 3 up with the 3 down
∴ f(g(x)) = x
→ Find g(f(x)) by substitute x in g(x) by f(x)
∴ g(f(x)) = 
→ Cancel the 3 up with the 3 down
∴ g(f(x)) = 
→ Cancel the square root with power 2
∴ g(f(x)) = x
∵ f(g(x)) = g(f(x)) = x
→ By using the rule above
∴ f(x) and g(x) are inverse functions
Answer:
5/12
Step-by-step explanation:
sorry if I'm incorrect can you mark brainiest please
1/4(2x - 14) = 4....multiply both sides by 4
2x - 14 = 4 * 4
2x - 14 = 16
2x = 16 + 14
2x = 30
x = 30/2
x = 15 <==
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