Multiply the number 12×8×6 that equal 576 :)
The perimeter of the entire figure is 62.8 cm.
Given, that the diameter of the inner semicircles is 9 cm and the width between the outer and inner semicircles is 2 cm.
The radius of the inner semicircle =4.5 cm and the radius of outer semicircle =5.5 cm (∵Diameter=9+2=11 cm)
We need to find the perimeter of the entire figure.
<h3>What is the perimeter?</h3>
A perimeter is a closed path that encompasses, surrounds, or outlines either a two-dimensional shape or a one-dimensional length. The perimeter of a circle or an ellipse is called its circumference.
We know that, the circumference of a semicircle=πr and the circumference of two semicircles=2πr
Thus, the circumference of inner semicircles=2×3.14×4.5=28.26 cm
The circumference of outer semicircles=2×3.14×5.5=34.54 cm
The perimeter of the entire figure=28.26+34.54=62.8 cm
Therefore, the perimeter of the entire figure is 62.8 cm.
To learn more about the perimeter visit:
brainly.com/question/6465134.
#SPJ1
SO x plus 17 are equal to 32. That means you know that 17 plus some unknown number can equal 32. To find this number, simply subtract 17 on both sides. This will get you x=15. Hope it helps.
The expected value of the outcome of the bid is $0.18
So let's start by counting how many bids are placed up to a total of 160.
100*160 = 16000.
What will be your arbitrary bid? As each bid has an equal chance of success, the average of all bids is used. (One cent plus 160 dollars) / 2 = 80 dollars (rounded)
Your odds of winning are 1/16000 (1 bid out of 16000).
If you win, your profit is 1920 ($2000 minus $80.00).
1920/16000 is $0.12
Your cost to enter the auction is $1, and your average winning offer is $0.12.
The result is $0.18 (0.12-1=-0.88).
Thus the expected value of the outcome of the bid is $0.18
Learn more about expected value here :
brainly.com/question/23509883
#SPJ1
Answer:
Events A and B are independent if the equation P(A∩B) = P(A) · P(B) holds true. You can use the equation to check if events are independent; multiply the probabilities of the two events together to see if they equal the probability of them both happening together.
