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olasank [31]
3 years ago
9

With similar triangles, the ratios off all three pairs of corresponding sides are equal.

Mathematics
2 answers:
Art [367]3 years ago
8 0

The answer is B. False

NNADVOKAT [17]3 years ago
4 0

Correct answer should be B. False.

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Identify the zero(s) of <img src="https://tex.z-dn.net/?f=f%28x%29%3D4x%5E%7B2%7D%20-%2020x%20-%2056" id="TexFormula1" title="f(
AURORKA [14]

Answer:

x = - 2, x = 7

Step-by-step explanation:

Given

f(x) = 4x² - 20x - 56

To find the zeros let f(x) = 0, that is

4x² - 20x - 56 = 0 ( divide through by 4 )

x² - 5x - 14 = 0 ← in standard form

(x - 7)(x + 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

x - 7 = 0 ⇒ x = 7

5 0
2 years ago
Solve the equation 2x²-x=0
Marta_Voda [28]
Factor

x(2x-1)=0

x = 1/2, 0
8 0
3 years ago
Read 2 more answers
5x +y=8
makvit [3.9K]
Take away the bottom equation from the top so the y’s cancel out
3x = -24
x therefore = -8
and put x back into the equation to find out y
2(-8) + y= 32
-16 + y =32
y= 48
6 0
2 years ago
A car moving at a constant speed passed a timing device at t=0. After 9 ​seconds, the car has traveled 837 ft. Write a linear fu
diamong [38]

Answer:

at t=0 the car has moved 0 feet, also you know it has a constant speed so you get the points:

P1:(0,0) therefore you know b, the y-intercept=0

P2:(8,840)

insert P2 into y=mx+b

840=8m+0

840/8=m

105=m

so the result is:

y=105x=105t=f(t)=d

Step-by-step explanation:

7 0
2 years ago
What is f(5) if f(1) = 3. 2 and f(x 1) = Five-halves(f(x))?
stealth61 [152]

Function assign value from one set to another. The value of f(5), if f(1) = 3.2 and f(x+1) = Five-halves(f(x)) is 125.

<h3>What is Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

As it is given the value of the function f(1) is 3.2, while the value of f(x+1) is f(x+1) = \dfrac{5}{2}[f(x)], therefore, in order to find the value of f(5), we need to calculate the value of f(4).

f(2)

f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(2)=f(1+1) = \dfrac{5}{2}[f(1)]\\\\f(2) = 2.5 \times 3.2\\\\f(2) = 8

f(3)

f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(3)=f(2+1) = \dfrac{5}{2}[f(2)]\\\\f(3) = 2.5 \times 8\\\\f(3) = 20

f(4)

f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(4)=f(3+1) = \dfrac{5}{2}[f(3)]\\\\f(4) = 2.5 \times 20\\\\f(4) = 50

f(5)

f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(5)=f(4+1) = \dfrac{5}{2}[f(4)]\\\\f(5) = 2.5 \times 50\\\\f(5) = 125

Hence, the value of f(5), if f(1) = 3. 2 and f(x+1) = Five-halves(f(x)) is 125.

Learn more about Function:

brainly.com/question/5245372

8 0
1 year ago
Read 2 more answers
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