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LUCKY_DIMON [66]
3 years ago
6

HELP ASAP!! ILL MARK BRAINLIEST! David recorded the ages, in years, of the members of four high school clubs. Each club has the

same number of members. A brief description of David’s data is shown.
Music Club: This club has the same number of members older than 16 and younger than 16.
Physics Club: This club has the greatest number of older members.
Sports Club: This club has the greatest number of younger members.
History Club: This club has the oldest member enrolled.
David then made box plots showing his data. Match the labels of the clubs to the box plots. Drag and drop each club into the indicated rectangles.

Mathematics
1 answer:
Dmitry [639]3 years ago
6 0

Answer:

Music club last box

Reason: There are equal number if members

Physics club first box

Reason: There are more older than young people

Sports Club third box

Reason: There are more younger people than older people

History Club takes the second box

Step-by-step explanation:

Hope this helps please like and mark as brainliest

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Simplify 18 - 2[X + (x - 5)].<br> 8- 4x<br> 28 - 4x<br> 28 - 2x
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Answer:

28 - 4x

Step-by-step explanation:

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Without graphing or solving either system of equations explain how you know what the solution to the system is.
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x = 5

y = -1

Step-by-step explanation:

from second equation,

  • y = -2 + 1
  • y = -1

by putting the value of y in first equation

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3 0
4 years ago
A number m is more than -7 2/3 or at most -10
frutty [35]

This situation is represented by the following disjoint inequality:

m > -\frac{23}{3} \cup m \leq -10

---------------------------

  • The format of a <u>disjoint inequality</u> is:

x > a \cup x \leq b

  • Which is read as: x is more than a or at most b.

---------------------------

  • In this question, we have number m more than -7\frac{2}{3} = -7 - \frac{2}{3} = -\frac{21}{3} - \frac{2}{3} = -\frac{23}{3} and at most -10, thus, the disjoint inequality that represents this situation is:

m > -\frac{23}{3} \cup m \leq -10

A similar problem is given at brainly.com/question/24528399

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