Plz help i need it!!

Mathematics

1 answer:

Umnica [9.8K]3 years ago

6 0

Answer: c) 19,807

<u>Step-by-step explanation:</u>

$A=A_o\cdot e^{kt}\\\\\bullet A_o\text{ is the initial population}\\\bullet \text{k is the rate of decrease}\\\bullet \text{t is the number of years after 2010}\\\\A=22,000\cdot e{(-0.021)(5)}\\.\ =22,000\cdot e^{-0.105}\\.\ =19,807$

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A random sample of 130 students is chosen from a population of 4,500 students. The mean IQ in the sample is 120, with a standard

barxatty [35]

Answer:

$120-2.614\frac{5}{\sqrt{130}}=118.85$

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Step-by-step explanation:

Information given

$\bar X= 120$ represent the sample mean

$\mu$ population mean (variable of interest)

s=5 represent the sample standard deviation

n=130 represent the sample size

For this case we can't set a margin of error just with a % since they not specify 1.13% respect to something for this case we can omit this value

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

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$df=n-1=130-1=129$

The Confidence level is 0.99 or 99%, the significance would be $\alpha=0.01$ and $\alpha/2 =0.005$ , and the critical value would be $t_{\alpha/2}=2.614$