Just plug in 2 for p. 3*2 - 2 = 6-2 = 4
Answer:
perpendicular(p)=5
base(b)=12
hypotenuese(h)=?
using pytha goras theorem,
h^2=P^2+b^2
h^2=(5)^2+(12)^2
h^2=25+144
h^2=169
h^2=13^2
h=13.
Let r(cos O + i sin O) be a cube root of 125(cos 288 + i sin 288)
then
r^3(cos O + i sin O)^3 = 125(cos 288 + i sin 28)
so r^3 = 125 and cos 3O + i sin 3O = cos 288 + i sin 288
so r = 5 and 3O = 288 + 360p and O = 96 + 120p
so one cube root is 5 (cos 96 + i sin 96)
Im a little rusty at this stuff Its been a long time.
Im not sure of the other 2 roots
sorry cant help you any more
