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Helen [10]
3 years ago
7

The length of a rectangular wire frame with dimensions of 12 cm × 8 cm increases at the rate of 0.5 cm per second, while its wid

th changes such that the perimeter remains the same. What part of the area of the initial rectangle is the area of the final rectangle after 8 seconds ?
Mathematics
1 answer:
arsen [322]3 years ago
7 0

Answer:

2/3

Step-by-step explanation:

Since the length increases by 0.5 cm every second, after 8 seconds the length will increase by 4 cm. 12 + 8 + 12 + 8 = 40, and 40 - (16 + 16) = 8. 8/2 = 4, so the width is now 4. 16 * 4 = 64, and 12 * 8 = 96. 64/96 = 2/3.

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Each side of the smaller square in the figure below is n inches long, and each side of the larger square is p inches longer than
lana66690 [7]

Answer:

2np + p²

Step-by-step explanation:

The general formula for the area of a square is A = s², where s = the length of one side of the square.  In the case of the smaller square the area would be: n x n = n².  Since the side of the larger square is 'p' inches longer, the length of one side is 'n + p'.  To find the area of the larger square, we have to take the length x length or (n +p)².

Using FOIL (forward, outside, inside, last):

(n + p)(n+p) = n² + 2np + p²

Since the area of the first triangle is n², we can subtract this amount from the area of the larger square to find out how many square inches greater the larger square area is.

n² + 2np + p² - n² = 2np + p²


8 0
3 years ago
Help me with this one please
galben [10]

Answer:

I think the top and the two in the middle but I can't really see it's a blurry picture

7 0
3 years ago
State the domain and range<br> {(2,4), (3,7), (4,9), (6,11)}
mihalych1998 [28]

Answer:

Domain= 2,3,4,6

Range=4,7,9,11

or

Domain [2,6]

Range [4,11]

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Consider the differential equation x2y′′ − 9xy′ + 24y = 0; x4, x6, (0, [infinity]). Verify that the given functions form a funda
pantera1 [17]

Answer:

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

y= c_1x^4+c_2x^6

Step-by-step explanation:

Given equation is

x^2y'' - 9xy+24y=0

This Euler Cauchy type differential equation.

So, we can let

y=x^m

Differentiate with respect to x

y'= mx^{m-1}

Again differentiate with respect to x

y''= m(m-1)x^{m-2}

Putting the value of y, y' and y'' in the differential equation

x^2m(m-1) x^{m-2} - 9 x m x^{m-1}+24x^m=0

\Rightarrow m(m-1)x^m-9mx^m+24x^m=0

\Rightarrow m^2-m-9m+24=0

⇒m²-10m +24=0

⇒m²-6m -4m+24=0

⇒m(m-6)-4(m-6)=0

⇒(m-6)(m-4)=0

⇒m = 6,4

Therefore the auxiliary equation has two distinct and unequal root.

The general solution of this equation is

y_1(x)=x^4

and

y_2(x)=x^6

First we compute the Wronskian

W(x)= \left|\begin{array}{cc}y_1(x)&y_2(x)\\y'_1(x)&y'_2(x)\end{array}\right|

         = \left|\begin{array}{cc}x^4&x^6\\4x^3&6x^5\end{array}\right|

         =x⁴×6x⁵- x⁶×4x³    

        =6x⁹-4x⁹

        =2x⁹

       ≠0

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

y= c_1x^4+c_2x^6

5 0
3 years ago
If 3(y+13) = 33 find the value of 1/4y
marshall27 [118]

Answer:

Step-by-step explanation:

3y + 39 = 33

3y = -6

y = -2

1/4(-2)= -2/4 = -1/2

3 0
3 years ago
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