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____ [38]
2 years ago
7

Translate each sentence into an equation. Then find each number.

Mathematics
2 answers:
jeka942 years ago
8 0

7n+(3+2n)=30

n=3

[ Plug it in to check if the answer is correct;

7(3)+(3+2(3))=30

21+9=30

30=30 ]

vaieri [72.5K]2 years ago
6 0

Answer:

7n+(3+2n)=30

Step-by-step explanation:

The number (n) is 3.

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What is the solution(s) to the system of equations y = x² +4 and y = 2x + 4
bija089 [108]

Answer:

(x,y) = (0,4)~ \text{and}~ (x,y) = (2,8)

Step by step explanation:

y = x^2 +4~~~~~~~~~...(i)\\\\y = 2x +4~~~~~~~~~...(ii)\\\\\text{From (i) and (ii):}\\\\~~~~~~x^2 +4 = 2x+4\\\\\implies x^2 = 2x\\\\\implies x^2 -2x = 0\\\\\implies x(x-2) = 0\\\\\implies x =0,~ x = 2

\text{Substitute x = 0 in eq (i):}\\\\y = 0^2 +4 = 4\\\\\text{Substitute x = 2 in eq (i):}\\\\y=2^2+4 = 4+4 = 8\\\\\text{Hence,}~ (x,y)= \{(2,8), (0,4)\}

3 0
1 year ago
WILL MARK BRAINLIEST PLEASE HELP THIS IS DUE NOW AND NO LINKS!!!
AveGali [126]

Answer:

1/49

<em>Step by step explanation:</em>

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2 years ago
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If an object is projected upward with an initial velocity of 126 ft per​ sec, its height h after t seconds is h= -16^2+126t. Fin
Phoenix [80]
All you would have to do is plug in 5 for t since that is the time; then you would see that the height of the object after 5 seconds is 886 ft. Hope this helped!
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Find the exact value of each trigonometric function for the given angle θ.
Kay [80]

Answer:

\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=\dfrac{2}{\sqrt{3}}.

Step-by-step explanation:

The given angle is 240 degrees.

We need to find the exact value of each trigonometric function for the given angle θ.

Since \theta=240, it means θ lies in 3rd quadrant. In 3d quadrant only tan and cot are positive.

\sin (240^\circ)=\sin (180^\circ+60^\circ)=-\sin (60^\circ)=-\dfrac{\sqrt{3}}{2}

\cos (240^\circ)=\cos (180^\circ+60^\circ)=-\cos (60^\circ)=-\dfrac{1}{2}

\tan (240^\circ)=\tan (180^\circ+60^\circ)=\tan (60^\circ)=\sqrt{3}

\cot (240^\circ)=\cot (180^\circ+60^\circ)=\cot (60^\circ)=\dfrac{1}{\sqrt{3}}

\sec (240^\circ)=\sec (180^\circ+60^\circ)=-\sec (60^\circ)=-2

\csc (240^\circ)=\csc (180^\circ+60^\circ)=-\csc (60^\circ)=-\dfrac{2}{\sqrt{3}}

Therefore, \sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=-\dfrac{2}{\sqrt{3}}.

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2 years ago
Is it true or false? And how
olasank [31]

The answer is false.

Counterexample:

If a = 4 and b = 2

(4 - 2)^2 = 4

4^2 - 2^2 = 12

Since these answers are not the same this equation is false.

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3 years ago
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