Part A. You have the correct first and second derivative.
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Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.
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Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out
To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0.
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well.
So the groups of angles that make a line (like 130 and i or p a and t) should equal 180. however, the triangles should also equal 180. so in this case for the top row, we know that 130+j=180. since 180-130=50 (i did the inverse of addition, subtraction), j=50. now let’s say for that triangle that your top two angle measures were the 50 we just found and the 70 you have written just as an assumption but i have no clue what you were actually given. since triangles angles must equal 180, 50+70+that angle =180. 50+70=120, so if we do the inverse of 180-120=60, we find out that the bottom angle is 60 degrees.
The gcf of the numbers are 15
Answer:
ok
Step-by-step explanation:
9+10=21
