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solmaris [256]
3 years ago
9

Write this expression using exponents 34

Mathematics
1 answer:
Mariana [72]3 years ago
8 0

Answer: 17²

Step-by-step explanation:

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Mr. Nelson lost one of his students' test
amid [387]

Complete question :

Mr. Nelson lost one of his students' test papers. He knows that the other 4 students scored as follows: 60, 62, 56, 57. He also knows that the average score is 59.2. What is the score on the missing paper?

Answer:

61

Step-by-step explanation:

Given the following :

Total number of students = 4 + 1 missing = 5

Score on the four avaliable papers = 60, 62, 56, 57

Average score of the 5 papers = 59.2

Score on missing paper :

Sum of each score / number of papers

Sum of each score = sum of available scores + missing score

Let missing score = m

(60 + 62 + 56 + 57 + m) = 235 + m

Recall:

Average = total sum / number of observations

Hence,

59.2 = (235 + m) / 5

59.2 × 5 = 235 + m

296 = 235 + m

m = 296 - 235

m = 61

Missing score = 61

6 0
3 years ago
Carla wants to start a college fund for her daughter Lila. She puts $63,000 into an account that grows at a rate of 2.55% per ye
Oksanka [162]

Answer:

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = 63000

r = 2.55% = 2.55/100 = 0.0255

n = 12 because it was compounded 12 times in a year.

Therefore, function, C(t), that represents the amount of money in the account t years after the account is opened is

C(t) = 63000(1 + 0.0255/12)^12t

C(t) = 63000(1.002125)^12t

For C(t) = 100000,

100000 = 63000(1.002125)^12t

100000/63000 = (1.002125)^12t

1.587 = 1.002125)^12t

Taking log of both sides

Log 1.587 = log 1.002125)^12t

Log 1.587 = 12tlog 1.002125)^

0.2005 = 12t × 0.00092

0.2005 = t × 0.01104

t = 0.2005/0.01104

t = 18.16 years

5 0
3 years ago
Let X denote the total snowfall in the Twin Cities in December of a given year, measured in centimeters. The five-number summary
Gre4nikov [31]

Answer:

Concept: Caclulating Standard Variables

  1. We have a five number summary which is more than enough information to calculate our mean.
  2. The mean is the sum of all the numbers divided by the nth number of numbers.
  3. Note that we can only find a rough estimation not the EXACT value
  4. We do (min +max + 2(Q1+median+Q3))/8
  5. Now let's plug in our values!
  6. (0+85.3+2(8.4+17.4+30.9))/8
  7. Which gives us option B
  8. Hope this helps, give brainlist

3 0
3 years ago
15<br>a) 5<br>5 +<br>8<br>27<br>of 1<br>+<br>99<br>5​
velikii [3]

Answer:

5 5 + 8 27 of 1 + 99 5​= 150

Step-by-step explanation:

Add the expressions.

7 0
3 years ago
Willis tower in Chicago is 1450 feet tall. The John Hancock Center in Chicago is 1127 feet tall. Suppose you are asked to build
gayaneshka [121]

Answer:

Small Scale replica of John Hancock tower is approximately 2.33 m.

Step-by-step explanation:

Given:

Height of Willis tower = 1450 ft

Height of John Hancock Center = 1127 ft

Small Scale replica of Willis tower = 3 m

We need to find Small Scale replica of John Hancock tower.

First we will find the per meter scale of Willis tower and then using the same we will use to find the Small Scale replica height of John Hancock tower.

For 3 meter scaling = 1450 ft

So for 1 meter scaling = Number of foots in 1 meter Scaling

By Using Unitary method we get;

Number of foots in 1 meter Scaling = \frac{1450}{3} = 483.333 \ ft

Now we had 1 meter scaling as 483.333 ft and we need to find meter scaling for 1127.

So again Using Unitary method we get;

Small Scale replica of John Hancock = \frac{1127}{483.333} = 2.331 \ m

Rounding to nearest hundred we get;

Small Scale replica of John Hancock tower is approximately 2.33 m.

8 0
3 years ago
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