Base 10 has the ten digits: {0, 1, 2, 3, 4, 5, 6,7, 8, 9}
Base 11 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A} where A is treated as a single digit number
Base 12 has the digits {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B}
Base 13 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C}
Base 14 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D}
The digit D is the largest single digit of that last set. So the largest 3-digit base 14 integer is DDD which is the final answer
Note: It is similar to how 999 is the largest 3-digit base 10 integer
Answer:
c=
−4
3
s−t+
−4
3
Step-by-step explanation:
Let's solve for c.
3s+2t−3c−7s−5t=4
Step 1: Add 4s to both sides.
−3c−4s−3t+4s=4+4s
−3c−3t=4s+4
Step 2: Add 3t to both sides.
−3c−3t+3t=4s+4+3t
−3c=4s+3t+4
Step 3: Divide both sides by -3.
−3c
−3
=
4s+3t+4
−3
c=
−4
3
s−t+
−4
3
