All categories

3 years ago

This spinner has 6 equal sections. What are the odds in simplest form against spinning blue or yellow?

Mathematics

2 answers:

astra-53 [7]3 years ago

5 0

Answer:

so the answer is A,B

Rolling two six-sided dice: Each die has 6 equally likely outcomes, so the sample space is 6 • 6 or 36 equally likely outcomes. Flipping three coins: Each coin has 2 equally likely outcomes, so the sample space is 2 • 2 • 2 or 8 equally likely outcomes.

Step-by-step explanation:

MariettaO [177]3 years ago

3 0

B) Th chance of getting yellow and blue would be 2/6 but not getting it would be 4/6 and 4/6 in its simplest form is 2/3

You might be interested in

jekas [21]

Given: In the given figure, there are two equilateral triangles having side 50 yards each and two sectors of radius (r) = 50 yards each with the sector angle θ = 120°

To Find: The length of the park's boundary to the nearest yard.

Calculation:

The length of the park's boundary (P) = 2× side of equilateral triangle + 2 × length of the arc

or, (P) = 2× 50 yards + 2× (2πr) ( θ ÷360°)

or, (P) = 2× 50 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)

or, (P) = 100 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)

or, (P) = 100 yards + 209.33 yards

or, (P) = 309.33 yards ≈309 yards

Hence, the option D:309 yards is the correct option.

7 0

3 years ago

Read 2 more answers

The ratio of boys to girls in a class is 5 to 6 which is an equivalent. Ratio

Vlad1618 [11]

There are many possible answers.
10:12
15:18
20:24
25:30
30:36

6 0

3 years ago

Read 2 more answers

A confidence interval was used to estimate the proportion of statistics students that are female. A random sample of 72 statisti

jeyben [28]

Answer:

We need a sample of size at least 13.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

90% confidence interval: (0.438, 0.642).

The proportion estimate is the halfway point of these two bounds. So

$\pi = \frac{0.438 + 0.642}{2} = 0.54$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Using the information above, what size sample would be necessary if we wanted to estimate the true proportion to within ±0.08 using 95% confidence?

We need a sample of size at least n.

n is found when M = 0.08. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.08 = 1.96\sqrt{\frac{0.54*0.46}{n}}$