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julia-pushkina [17]
3 years ago
14

The scale for the drawing below is 1 in = 2 in. Draw the larger figure and label the sides. By

Mathematics
1 answer:
arlik [135]3 years ago
4 0

Answer:

i need the answer too :(

Step-by-step explanation:

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What is the image point of
Ganezh [65]

Answer:

<h3>               (8, -5)</h3>

Step-by-step explanation:

Translation right (or left) means change of the x-coordinate.

Translation down (or up) means change of the y-coordinate.

(5, -4)   →    (5+3, -4-1) = (8, -5)

6 0
3 years ago
A random sample of 9 wheels of cheese yielded the following weights in pounds has a sample mean of 20.90 and a sample variance o
Ronch [10]

Answer:

2.002 \leq \sigma^2 \leq 11.365

Step-by-step explanation:

1) Data given and notation

s represent the sample standard deviation

s^2 represent the sample variance

n=9 the sample size

Confidence=90% or 0.90

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

On this case we need to find the sample standard deviation with the following formula:

s=sqrt{\frac{\sum_{i=1}^9 (x_i -\bar x)^2}{n-1}}&#10;The sample variance given was [tex]s^2=3.45

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=9-1=8

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,8)" "=CHISQ.INV(0.95,8)". so for this case the critical values are:

\chi^2_{\alpha/2}=15.507

\chi^2_{1- \alpha/2}=2.732

And replacing into the formula for the interval we got:

\frac{(9)(3.45)}{15.507} \leq \sigma \frac{(9)(3.45)}{2.732}

2.002 \leq \sigma^2 \leq 11.365

7 0
3 years ago
Jerry had $1,018.00 in savings. Last week he spent $84.00 on a desk and $372.00 on a computer from his savings. This week at a p
iris [78.8K]
1018-606=412. Hope it helps
7 0
3 years ago
The ladder he uses makes a 75° angle with the ground. What is thhe shortest possible length of the ladder if the top of it is 23
Viefleur [7K]

your answer would be

24 FEET

5 0
3 years ago
Read 2 more answers
Please show working out, thanks!
sveticcg [70]
3^2x = 2^3y = x/y = x/y
4 0
3 years ago
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