The expected length of code for one encoded symbol is
where is the probability of picking the letter , and is the length of code needed to encode . is given to us, and we have
so that we expect a contribution of
bits to the code per encoded letter. For a string of length , we would then expect .
By definition of variance, we have
For a string consisting of one letter, we have
so that the variance for the length such a string is
"squared" bits per encoded letter. For a string of length , we would get .
Answer:
no it is not the same because you get different answers
Answer:
15/3 + (6.5 + 4.2) - 0.6 = 15.1
Step-by-step explanation:
You can first reduce the fraction to 5 when you multiply by 3, then calculate what's in the parenthesis. So now you have 5 + 10.7 - 0.6, then just solve from left to right. Hope this helps
5 km = 5000 M = 500000 Cm
Answer:
a
Step-by-step explanation:
i just took the test