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loris [4]
3 years ago
5

Are the two shapes are congruent?​

Mathematics
2 answers:
BaLLatris [955]3 years ago
5 0

Answer:

nah

Step-by-step explanation:

the distance between H and G is longer than the distance between C and D making it not congruent

Harman [31]3 years ago
4 0

Answer:

no they are not congruennt

Step-by-step explanation:

because the shape is not similar

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Clark has a box of nickels and dimes that totals $1.90. there are a total of 27 coins. how many nickels and dimes does he have?
Andrej [43]
$0.05(n) + $0.10(d) = $1.90
n + d = 27
n + d - d =27 - d
n = 27 - d

$0.05(27-d) + $0.10(d) = $1.90
1.35 - 0.05d + 0.10d = $1.90
1.35 +0.05d = $1.90
1.35 - 1.35 +0.05d = $1.90 -1.35
0.05d = 0.55
0.05d/0.05 = 0.55/0.05
d = 11

n = 27 - 11
n = 16

$0.05(16) + $0.10(11) = $1.90
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4 0
3 years ago
System of Equations <br> Need help<br> Trig
Yanka [14]

Looks like the system is

\begin{cases}-2x+y+6z=1\\3x+2y+5z=16\\7x+3y-4z=11\end{cases}

We can eliminate y by taking

(3x+2y+5z)-2(-2x+y+6z)=16-2(1)

\implies3x+2y+5z+4x-2y-12z=16-2

\implies7x-7z=14

\implies x-z=2

so that z=x-2, and

(7x+3y-4z)-3(-2x+y+6z)=11-3(1)

\implies7x+3y-4z+6x-3y-18z=11-3

\implies13x-22z=8

Substitute z=x-2 into this last equation and solve for x:

13x-22(x-2)=8

\implies13x-22x+44=8

\implies-9x=-36

\implies x=4

Then

z=x-2

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\implies z=2

Plug these values into any one of the original equation to solve for y:

-2x+y+6z=1

\implies-2(4)+y+6(2)=1

\implies-8+y+12=1

\implies y=-3

Hence the solution is x = 4, y = -3, and z = 2.

6 0
3 years ago
What is the area of a triangle with a base of 6mm and a height of 9mm
baherus [9]
Areaa= 0.5 b h
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pav-90 [236]
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