(L,L,L),(L,L,W),(L,W,L),(L,W,W),(W,L,L),(W,L,W),(W,W,L),(W,W,W) 8 total
Answer
n = 30
Explanation
To solve for n, you have to isolate it by 'getting rid' of the 18, 2, and negative sign.
You 'remove' these numbers in backward PEMDAS.
So to 'remove' the 18, you subtract both sides by 18.
3-18 = -15
-n/2+18-18 = -n/2
So now you are left with -15 = -n/2.
To 'get rid' of the 2, you multiply each side by 2.
-15×2 = -30
-n/2×2 = -n
And now you have -30 = -n.
To 'get rid' of the negative sign, you multiply both sides by -1.
-30×-1 = 30
-n×-1 = n
So you get 30 = n or n = 30.
If you still have questions I'll answer them in the comments (under this question).
27/12=2.25
2.25x7=15.75
ANSWER: $15.75 for 7 cans
I) HCF - use the smallest powers of each common factors
HCF (A,B) = 2^2 × 3^4 × 5^2
LCM - use the highest powers of each factors
LCM (A,B) = 2^4 × 3^6 × 5^2 × 7^2 × 11^16
ii) Add powers together.
A×B = 2^6 × 3^10 × 5^4 × 7^2 × 11^16
sqrt(A × B)
Divide powers by 2.
sqrt(A × B) = 2^3 × 3^5 × 5^2 × 7 × 11^8
iii) C = 3^7 × 5^2 × 7
Ck = (3^7 × 5^2 × 7) × k
B/c Ck should be a product that is a perfect cube, the powers of the products should be divisible by 3.
(3^7 × 5^2 × 7) × k = 3^9 × 5^3 × 7^3
k = (3^9 × 5^3 × 7^3) / (3^7 × 5^2 × 7)
k = 3^(9-7) × 5^(3-2) × 7^(3-1)
k = 3^2 × 5 × 7^2
