Question

I need an explanation for the problem 4v2=-12v-9. I don't understand why it factors into 4v+3 and 4v+3

Answer 1

Answer:

The factors are $2v+3,2v+3$.

The factors are not $4v+3,4v+3$

Step-by-step explanation:

Equation is $4v^2=-12v-9$.

This equation can be written as follows:

$4v^2+12v+9=0$

Here,

$12v=6v+6v$

Therefore,

$4v^2+6v+6v+9=0\\2v(2v+3)+3(2v+3)=0\\(2v+3)(2v+3)=0$

So, the factors are $2v+3,2v+3$.

The factors are not $4v+3,4v+3$