Answer:
x = 13.444 ... (repeating decimal) or;
x = 13 4/9
Step-by-step explanation:
-0.65 + 0.45x = 5.4
First we will add 0.65 to each 'side' of the equation.
0.65 + (-0.65) + 0.45x = 0.65 + 5.4
0.65 + (-0.65) = 0
0.65 + 5.4 = 6.05
Input the numbers, and now the equation looks like this:
0 + 0.45x = 6.05
Remove the zero:
0.45x = 6.05
Divide each 'side' by 0.45.
0.45x ÷ 0.45 = 6.05 ÷ 0.45
0.45x ÷ 0.45 = 1x = x
6.05 ÷ 0.45 = 13.444 ... repeating decimal
Input the numbers, and now the equation looks like this:
x = 13.444 ... repeating decimal
We can also write this as:
x = 13 4/9 in fraction form
Given:
Karen earns $54.60 for working 6 hours.
Amount she earns varies directly with the number of hours she works.
She need to work to earn an additional $260.
To find:
Number of hours she need to work to earn an additional $260.
Solution:
Let the amount of earnings be A and number of hours be t.
According to question,
![A\propto t](https://tex.z-dn.net/?f=A%5Cpropto%20t)
...(i)
where, k is constant of proportionality.
Karen earns $54.60 for working 6 hours.
![54.60=k(6)](https://tex.z-dn.net/?f=54.60%3Dk%286%29)
Divide both sides by 6.
![\dfrac{54.60}{6}=k](https://tex.z-dn.net/?f=%5Cdfrac%7B54.60%7D%7B6%7D%3Dk)
![9.1=k](https://tex.z-dn.net/?f=9.1%3Dk)
Put k=9.1 in (i).
![A=9.1t](https://tex.z-dn.net/?f=A%3D9.1t)
Substitute A=260 in the above equation.
![260=9.1t](https://tex.z-dn.net/?f=260%3D9.1t)
Divide both sides by 9.1.
![\dfrac{260}{9.1}=t](https://tex.z-dn.net/?f=%5Cdfrac%7B260%7D%7B9.1%7D%3Dt)
![28.5714=t](https://tex.z-dn.net/?f=28.5714%3Dt)
![t\approx 29](https://tex.z-dn.net/?f=t%5Capprox%2029)
Therefore, she need to work extra about 29 hours to earn an additional $260.
Step-by-step explanation:
The answer which you have chosen is <u>correct</u>.
Answer:
21z+84
Step-by-step explanation.
7x3=21 then put the z at the end 21z.
7x12=84. Put it after the 21z. 21z+84
Answer:
Your answer is B
Step-by-step explanation:
If you use the division you technically can't use the distributive property, so it could be A. But if you had to use it; I would say the best way to do so it to multiply everything by 1.