we are given
now, we can compare it with
we can find b
we get
now, we are given
How would the graph change if the b value in the equation is decreased but remains greater than 1
Let's take
b=1.8
b=1.6
b=1.4
b=1.2
now, we can draw graph
now, we will verify each options
option-A:
we know that all y-value will begin at y=0
because horizontal asymptote is y=0
so, this is FALSE
option-B:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
option-C:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is TRUE
option-D:
we know that curves are increasing
so, the value of y will keep increasing as x increases
so, this is TRUE
option-E:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
You could use change of base formula
Answer: About
Step-by-step explanation:
The missing figure is attached.
Notice in the first picture that Alberta has a complex shape.
You can calculate the area of a complex shape by decomposing it into polygons whose areas can be calculated easily.
Observe the second picture. Notice that it can be descompose into two polygons: A trapezoid and a rectangle.
The area of the trapezoid can be calcualted with the formula:
Where "h" is the height, "B" is the long base and "b" is short base.
And the area of the rectangle can be found with the formula:
Wkere "l" is the lenght and "w" is the width.
Then, the apprximate area of Alberta is:
Substituting vallues, you get:
Therefore, the area of of Alberta is about .
Answer:
1/6
Step-by-step explanation:
5/6 divided by 5 is 1/6