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ExtremeBDS [4]
3 years ago
6

Where the numerator is larger than the denominator

Mathematics
2 answers:
gregori [183]3 years ago
4 0
A fraction with a numerator that is greater than or equal to the denominator is known as an improper fraction.
Karo-lina-s [1.5K]3 years ago
4 0

Answer:

Step-by-step explanation:

If you are looking for an example of a fraction where the numerator is larger than the denominator, it would be 12/6. But that is just an example. There are many more.

That can be reduced to 2 btw.

Hope this helps.

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Greta read a 900 pages book in 15 days, reading for 5 hours every day.
lapo4ka [179]
So she reads for 5 hours every day for 15 days, how many hours is that?  well is just 5*15, or 75 hours.

so, she reads 900 pages in 75 hours, how many pages does she do in 1 hour?

\bf \begin{array}{ccll}
pages&hours\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
900&75\\
p&1
\end{array}\implies \cfrac{900}{p}=\cfrac{75}{1}\implies \cfrac{900\cdot 1}{75}=p
3 0
3 years ago
What value of n makes the equation true?
djverab [1.8K]
0.7n + 0.8n = 2.1
1.5n = 2.1 (add like terms(0.7+0.8=1.5))
n=2.1/1.5 (get en on its own)
n=1.40
3 0
3 years ago
Find two consecutive integers whose sum is 77​
Semenov [28]

Answer:

<h3>                 38, 39 </h3>

Step-by-step explanation:

The difference between two consecutive integers is 1

So if

x  - the smaller number

then

x+1   - the larger number

x + x+1 = 77

  -1          -1

2x = 76

÷2    ÷2

 x = 38

x+1 = 38+1 = 39

7 0
3 years ago
Write the sum of the circumferences of all three circles in factored form.
salantis [7]

Answer:

2π(x+y+z)

is the factorization

4 0
2 years ago
Grades in large classes are sometimes approximately Normally distributed—a fact that serves as the justification for "grading on
QveST [7]

Answer:

Grade A: Z \geq 1

Grade B: 0 \leq Z < 1

Grade C: -1 \leq Z < 0

Grade D: Z < -1

Step-by-step explanation:

Problems of normally distributed samples can be solved using the Z score table.

The Z score of a measure represents how many standard deviations it is above or below the mean of all the measures.

Each Z score has a pvalue. This represents the percentile of the measure.

In this problem, we have that:

The upper 16% of the class get A grades. The upper 16% has a pvalue of at least 100% = 16% = 84% = 0.84. This is Z \geq 1.

The middle 34% of the class get B grades. The middle 34% has a pvalue of at least 84%-35% = 50% = 0.5 and at most 0.84. This is 0\leqZ < 1.

Those between a pvalue of 0.5-0.34 = 0.16 and 0.5 get get grade C. Z = -1 has a pvalue of 0.16. So a grade C is in the interval -1 \leq Z < 0.

Those with Z lesser than -1 get grades D and F

6 0
3 years ago
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