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zzz [600]
4 years ago
7

A study found that 9% of dog owners brush their dog’s teeth. Of 578 dog owners, about how many would be expected to brush their

dog’s teeth? Explain.
1 point
50; 9% ≈ 10% and 578 should be rounded down to 500; 10% of 500 = 50
60; 9% ≈ 10% and 578 ≈ 600; 10% of 600 = 60
70; 9% ≈ 10% and 578 ≈ 700; 10% of 700 = 70
100; 9% ≈ 10% and 578 should be rounded up to 1,000; 10% of 1,000 = 100
Mathematics
1 answer:
GenaCL600 [577]4 years ago
0 0

Answer:

9 percent of 578 is 52.02.

Step-by-step explanation:

578/x=100/9

(578/x)*x=(100/9)*x       - we multiply both sides of the equation by x

578=11.111111111111*x       - we divide both sides of the equation by (11.111111111111) to get x

578/11.111111111111=x  

52.02=x  

x=52.02

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Simplify. -10m+2m^4-13m-20m^4
Ulleksa [173]
First one:

you can add -10m and -13m but you can't add -10m and 2m^4 becuase the powers aren't the same so

when adding the like terms
look at the:
powers, (x^3 adds with x^3)
placehloder letter (x adds with x and y adds with y and so on)

-10m+2m^4-13m-20m^4
powers: m^1 and M^4
placeholders: all m


add
-10m-13m+2m^4-20m^4
-23m-18m^4




second one:
when multiplying exponents, you add with like
so if you multipliy
x^2yz^3 times x^4y^2z^2 thne you would get x^6y^3z^5
when multiply with coeficients
2x^2yz^3 times 4x^4y^2z^2=8x^6y^3z^5
so using associative property a(bc)=(ab)c
2/3 times p^4 times y^3 times y^4 times s^5 times 6 times p^2 times s^3
group like terms

(2/3 times 6) times (p^4 times p^2) times (y^3 times y^4) times (s^5 times s^3)
(4) times (p^6) times (y^7) times (s^8)
4p^6y^7s^8

8 0
3 years ago
Jen measured the growth of a sunflower in one week it grew 2 and 1 half in
Pie
So you basically add the amount it grew each week. So week one is 2 and 1/2, week two is 2 and 3/4 and week three is 3 and 1/4. to make things simpler, add week two and three which gets you 6inches, then add week one, to get 8 and a half inches.
8 0
3 years ago
-17xy + 5x - (-25xy) - 5x
poizon [28]

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3 0
3 years ago
What is the sequence of transformations that maps △ABC to △A′B′C′ ? Select from the drop-down menus to correctly identify each s
torisob [31]
<h3>Answer:</h3>

Any 1 of the following transformations will work. There are others that are also possible.

  • translation up 4 units, followed by rotation CCW by 90°.
  • rotation CCW by 90°, followed by translation left 4 units.
  • rotation CCW 90° about the center (-2, -2).
<h3>Step-by-step explanation:</h3>

The order of vertices ABC is clockwise, as is the order of vertices A'B'C'. Thus, if reflection is involved, there are two (or some other even number of) reflections.

The orientation of line CA is to the east. The orientation of line C'A' is to the north, so the figure has been rotated 90° CCW. In general, such rotation can be accomplished by a single transformation about a suitably chosen center. Here, we're told there is <em>a sequence of transformations</em> involved, so a single rotation is probably not of interest.

If we rotate the figure 90° CCW, we find it ends up 4 units east of the final position. So, one possible transformation is 90° CCW + translation left 4 units.

If we rotate the final figure 90° CW, we find it ends up 4 units north of the starting position. So, another possible transformation is translation up 4 units + rotation 90° CCW.

Of course, rotation 90° CCW in either case is the same as rotation 270° CW.

_____

We have described transformations that will work. What we don't know is what is in your drop-down menu lists. There are many other transformations that will also work, so guessing the one you have available is difficult.

5 0
3 years ago
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Romashka [77]

Answer:

84

Step-by-step explanation:

A=bh/2.

A=(21*8)/2

A=168/2

A=84

6 0
3 years ago
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