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Aliun [14]
3 years ago
13

[x-(3-5i)][x-(3+5i)]

Mathematics
1 answer:
12345 [234]3 years ago
4 0
You would combine like terms to get x^2 - 6x + 34
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10 points, thank you in advance :)
Sophie [7]

Answer:

-3 + 10i

sqrt-100 = sqrt100i

sqrt100 = 10

So,

-3 + 10i

8 0
3 years ago
Y=x+5<br> y=-2x-4<br> use substitution
blondinia [14]
You have to do Y= -2+5-4
7 0
3 years ago
Calculate pt3 such that a line from pt1 to pt3 is perpendicular to the line from pt1 to pt2, and the distance between pt1 and pt
Leni [432]
Let the point_1 = p₁ = (1,4)
and      point_2 = p₂ = (-2,1)
and      Point_3 = p₃ = (x,y)

The line from point_1 to point_2 is L₁ and has slope = m₁
The line from point_1 to point_3 is L₂ and has slope = m₂
m₁ = Δy/Δx = (1-4)/(-2-1) = 1
m₂ = Δy/Δx = (y-4)/(x-1)
L₁⊥L₂ ⇒⇒⇒⇒ m₁ * m₂ = -1
∴ (y-4)/(x-1) = -1 ⇒⇒⇒ (y-4)= -(x-1)
(y-4) = (1-x) ⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒ equation (1)

The distance from point_1 to point_2 is d₁
The distance from point_1 to point_3 is d₂
d = \sqrt{Δx^2+Δy^2}
d₁ = \sqrt{(-2-1)^2+(1-4)^2}
d₂ = \sqrt{(x-1)^2+(y-4)^2}
d₁ = d₂
∴ \sqrt{(-2-1)^2+(1-4)^2} = \sqrt{(x-1)^2+(y-4)^2} ⇒⇒ eliminating the root
∴(-2-1)²+(1-4)² = (x-1)²+(y-4)²
 (x-1)²+(y-4)² = 18
from equatoin (1)  y-4 = 1-x
∴(x-1)²+(1-x)² = 18            ⇒⇒⇒⇒⇒ note: (1-x)² = (x-1)²
2 (x-1)² = 18
(x-1)² = 9
x-1 = \pm \sqrt{9} = \pm 3
∴ x = 4 or x = -2
∴ y = 1 or y = 7

Point_3 = (4,1)  or  (-2,7)












8 0
3 years ago
Helpp fast will name brainliest5. A worker drives 2 hours each day to work. Write an algebraic expression to represent the numbe
Alchen [17]
The first question is d 

i think the second one is c
8 0
3 years ago
Read 2 more answers
Solve for x.<br> -30 = 5(x + 1) <br>x=​
Alecsey [184]

Answer: -7

Step-by-step explanation:

-30 = 5(x + 1)

-30 = 5x + 5.  ( After distrbuting the 5)

-5.            -5

-30 - 5. = 5x

-35 = 5x

x = -7

5 0
3 years ago
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