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Mice21 [21]
3 years ago
13

In ΔJKL, the measure of ∠L=90°, KJ = 37, LK = 12, and JL = 35. What ratio represents the cosine of ∠J?

Mathematics
1 answer:
andrew-mc [135]3 years ago
5 0

Answer:

35/37

Step-by-step explanation:

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x= -11

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Which equation could be used to solve for the length of XY? XY = (22) sin (41°) XY = (22) cos (41°) XY = Start Fraction 22 Over
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Pythagorean's theorem: a²+ b²= c²

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Tangents: tan A = a/b, tan B = b/a.

Step-by-step explanation:

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Answer:

x =\sqrt{\frac{a^6m}{b^2}+n}

General Formulas and Concepts:

  • Order of Operations: BPEMDAS
  • Equality Properties
  • Exponent Power Rule: (b^m)^n=b^{mn}

Step-by-step explanation:

<u>Step 1: Define equation</u>

a\sqrt{\frac{x^2-n}{m} } =\frac{a^2}{b}

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Multiply <em>a</em> on both sides:                    \sqrt{\frac{x^2-n}{m} } =\frac{a^3}{b}
  2. Square both sides:                              \frac{x^2-n}{m} =(\frac{a^3}{b})^2
  3. Simplify:                                               \frac{x^2-n}{m} =\frac{a^6}{b^2}
  4. Multiply <em>m</em> on both sides:                   x^2-n =\frac{a^6}{b^2}m
  5. Add <em>n</em> to both sides:                           x^2 =\frac{a^6}{b^2}m+n
  6. Simplify:                                               x^2 =\frac{a^6m}{b^2}+n
  7. Square root both sides:                      x =\sqrt{\frac{a^6m}{b^2}+n}
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3 years ago
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