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2 years ago

Find the axis of symmetry and vertex for the parabola y=-4x^2-32x-10

Mathematics

2 answers:

KatRina [158]2 years ago

7 0

Answer:

the equation of the axis of symmetry is $x=-4$

Step-by-step explanation:

Recall that the x-value of the vertex of a parabola of the form:

$y=ax^2+bx +c$

is given by the expression:

$x_{vertex}=-\frac{b}{2\,a}$

therefore, in our case the x-position of the vertex becomes; $x_{vertex}=-\frac{b}{2\,a}=\frac{32}{-8} =-4$

and since the equation of the axis of symmetry is $x=x_{vertex}$

Then, the equation of the axis of symmetry is $x=-4$

Rom4ik [11]2 years ago

4 0

Answer:

Axis of Symmetry: x = -4

Vertex: (-4, 54)

Step-by-step explanation:

We use a graphing calc.

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lisov135 [29]

Answer:

The change in temperature per minute for the sample, dT/dt is 71. $\overline {6}$ °C/min

Step-by-step explanation:

The given parameters of the question are;

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The heat transfer rate for 1 kg of glass at 20.0 °C, dQ/dt = 12.9 kcal/min

Given that both dQ/dT and dQ/dt are known, we have;

$\dfrac{dQ}{dT} = 0.18 \, (kcal/ ^{\circ} C)$

$\dfrac{dQ}{dt} = 12.9 \, (kcal/ min)$

Therefore, we get;

$\dfrac{\dfrac{dQ}{dt} }{\dfrac{dQ}{dT} } = {\dfrac{dQ}{dt} } \times \dfrac{dT}{dQ} = \dfrac{dT}{dt}$

$\dfrac{dT}{dt} = \dfrac{\dfrac{dQ}{dt} }{\dfrac{dQ}{dT} } = \dfrac{12.9 \, kcal / min }{0.18 \, kcal/ ^{\circ} C } = 71.\overline 6 \, ^{\circ } C/min$

For the sample, we have the change in temperature per minute, dT/dt, presented as follows;

$\dfrac{dT}{dt} = 71.\overline 6 \, ^{\circ } C/min$

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2 years ago

If X is a rational number and Y is the opposite of X, why do X and Y have the same absolute value

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Goryan [66]

Answer:

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Step-by-step explanation:

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2 years ago

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3 years ago

PLEASE HELP ASAP!!!!!!

Natali5045456 [20]

Answer:

13.60 See the note below.

Step-by-step explanation:

Remark

This is just the reverse of the question you just did. This time you are trying to solve for c

Givens

a = 8
b = 11
c = ??

Solution

c^2 = a^2 + b^2 Substitute the givens.

c^2 = 8^2 + 11^2 Expand

c^2 = 64 + 121 Combine the right side by adding

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sqrt(c^2) = sqrt(185) Complete the operation

c = 13.601 Round to the nearest 1/100 th

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