Question

Find the axis of symmetry and vertex for the parabola y=-4x^2-32x-10

Answer 1

Answer:

the equation of the axis of symmetry is $x=-4$

Step-by-step explanation:

Recall that the x-value of the vertex of a parabola of the form:

$y=ax^2+bx +c$

is given by the expression:

$x_{vertex}=-\frac{b}{2\,a}$

therefore, in our case the x-position of the vertex becomes;$x_{vertex}=-\frac{b}{2\,a}=\frac{32}{-8} =-4$

and since the equation of the axis of symmetry is $x=x_{vertex}$

Then, the equation of the axis of symmetry is $x=-4$

Answer 2

Answer:

Axis of Symmetry: x = -4

Vertex: (-4, 54)

Step-by-step explanation:

We use a graphing calc.